Question

How many Coulombs of electricity are required for reduction of 1 mole of $MnO_{4}^{-}\text{to}Mn^{2 +}$

• A. 96500 C
• B. $1.93 \times 10^{5}C$
• C. $4.83 \times 10^{5}C$
• D. $9.65 \times 10^{6}C$

Answer 1

Answer: (C)

$4.83 \times 10^{5}C$

Answer 2

$(MnO_{4})^{-} \rightarrow Mn^{2 +}$ i.e., $Mn^{7 +} + 5e^{-} \rightarrow Mn^{2 +}$

Thus 1 mole of $MnO_{4}^{-}$requires 5 F

$= 5 \times 96500C = 482500$≃$4.83 \times 10^{5}C.$