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Question

Question: How many combinations can you make with the number \(1,2,3\)?...

How many combinations can you make with the number 1,2,31,2,3?

Explanation

Solution

Though this type of sum can be solved easily it would be great to to use the formula of Combinations to find the Answers. This is because if a student has the hang of using the formula for combinations and permutations it would become extremely easy for him to solve questions on probability, series numerical. In this particular numerical we would be using the formula nCr=n!r!(nr)!^n{C_r} = \dfrac{{n!}}{{r!\left( {n - r} \right)!}} to find the number of combinations.

Complete step-by-step answer:
In order to solve the numerical, we can say that the 3 digits need to be rearranged in any manner to find the number of combinations possible.
Thus we can say that for thousands of places the number of combinations possible are 3C1.......(1)^3{C_1}.......(1). This is because there are 33 numbers and only 11 blank space is available.
Now similarly finding the number of combinations for 100s100s place. Now since 11 digit has been used up in the thousands place, we are left with 22 digits and 11 blank space. Therefore the numbers of combinations possible are 2C1........(2)^2{C_1}........(2).
Now we are left with only 11 digit and we have only 11 blank space. The number of combinations possible are 1C1........(3)^1{C_1}........(3).
In order to find the total number of combinations, we will have to multiply the equation 1,2,31,2,3.
The total number of combinations are 3C1×2C1×1C1=3×2×1=6^3{C_1}{ \times ^2}{C_1}{ \times ^1}{C_1} = 3 \times 2 \times 1 = 6.
The list of combinations are as follows
123 132 213 231 312 321 \begin{gathered} 123 \\\ 132 \\\ 213 \\\ 231 \\\ 312 \\\ 321 \\\ \end{gathered}

Note: Though this sum looked easy, it could become tedious if there were more numbers of digits and we would find total combinations by just thinking and writing it down without the usage of the formula. For example, if there was a sum in which 66 digits were given and we had to find the number of combinations, it would be a 11 minute sum if we used the formula, on the contrary it would take a lot of time if we found the answer without any formula. Thus the student should start practicing the use of the formula.