Question
Question: How many cells each marked \(6V - 12A\) should be connected in mixed grouping so that he marked \(24...
How many cells each marked 6V−12A should be connected in mixed grouping so that he marked 24V−24A
A. 4
B. 8
C. 12
D. 6
Solution
In this problem the cell which is having emf of 6V and current of 12A is connected in different combinations that is series and parallel combination to obtain the emf of 24V and current of 24A .
Complete step-by-step solution:
If the cells are connected in series the resultant emf of the battery will be equal to sum of the emf of the individual cell and the current remains same .If E is the resultant emf of the of the battery with n number of cells and E1,E2,E3,E4.......En. are the emf of individual cells. Then
E=E1+E2+E3+E4.......+En.……… (1)
I remains the same.
If the cells are connected in parallel the resultant current of the battery will be equal to sum of the current of the individual cell and the emf remains same .If I is the resultant current of the of the battery with n number of cells and I1,I2,I3,I4.......In. are the current of individual cells. Then
I=I1,I2,I3,I4.......In. ……… (2)
E remains the same.
Given:
⇒ Each cell have emf of 6V and current of 12A
ε=6V,I=12A
This cell should be connected to get resultant emf of 24V and current of 24A
⇒ When 4 cells are connected in series the resultant emf is 24V and the current remains the same that is 12A because the current is same in series combination
ε=24V,I=12A
⇒ Then this combination is connected in parallel the resultant emf remains the same that is 24V because voltage or emf remains same in parallel combination and the current will be 24A
ε=24V,I=24A
Therefore, 8 cells are connected in mixed group as shown above to get, ε=24V,I=24A
Hence, option B is correct. That is 8
Note: In series connection the current will be the same and potential difference or voltage or emf will be different. Whereas in parallel combination the current will be different and the potential difference will be the same.