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Question: How many atoms or molecules are present in \(1.0mol\) of \(Au\)?....

How many atoms or molecules are present in 1.0mol1.0mol of AuAu?.

Explanation

Solution

As we are well aware with the term mole which is given as the ratio of the given mass of any substance or compound to the molecular mass of the given substance or compound. We can calculate it by knowing the mass and molecular mass of the compound. We also know the moles are directly related to the number of atoms as well as molecules and volume of a substance.

Formula used: moles×NA=no.of  atoms  or  moleculesmoles \times {N_A} = no.of\;atoms\;or\;molecules

Complete step-by-step answer:
As we already know the mole concept where a mole is defined when mass of a substance is divided by the molecular mass of that substance. It is expressed as shown below:
moles=massmolecular  massmoles = \dfrac{{mass}}{{molecular\;mass}}

Now, along with moles, we can also calculate the other parameters such as the volume of any substance at NTP or STP, number of atoms, number of molecules and many more in a given mass of any substance using the below formula:
moles=massmolecular  mass=vol.  at  STP22.4L=no.of  molecules  or  atomsNA\Rightarrow moles = \dfrac{{mass}}{{molecular\;mass}} = \dfrac{{vol.\;at\;STP}}{{22.4L}} = \dfrac{{no.of\;molecules\;or\;atoms}}{{{N_A}}}
Where NA{N_A} is Avogadro’s number.

So, using the above relation between moles and number of atoms and moles and number molecules we can easily identify the atoms or molecules of AuAu in given number of moles using:
moles=no.of  atoms  or  moleculesNA\Rightarrow moles = \dfrac{{no.of\;atoms\;or\;molecules}}{{{N_A}}}
We are given with 1.0mol1.0mol of AuAu, so after putting it in the formula we would get:
moles×NA=no.of  atoms  or  molecules\Rightarrow moles \times {N_A} = no.of\;atoms\;or\;molecules
no.of  atoms=1.0×6.022×1023\Rightarrow no.of\;atoms = 1.0 \times 6.022 \times {10^{23}}
no.of  atoms=6.022×1023\Rightarrow no.of\;atoms = 6.022 \times {10^{23}}
Similarly, we can calculate the number of molecules present in 1.0mol1.0mol of AuAu and they will be equivalent to:
no.of  molecules=1.0×6.022×1023\Rightarrow no.of\;molecules = 1.0 \times 6.022 \times {10^{23}}
no.of  molecules=6.022×1023\Rightarrow no.of\;molecules = 6.022 \times {10^{23}}

Therefore the correct answer is that 1.0mol1.0mol of AuAu contains the similar number of atoms or molecules as the Avogadro’s number.

Note: Always remember that the ratio of mass to the molecular mass is equivalent to its number of moles which in turn is equivalent to the ratio of number of atoms or number of molecules to the Avogadro’s number. We can also calculate the volume of a substance if we know its number of moles.