Question

How many atoms of lithium are contained in 6.22 moles of lithium?

Answer 1

We know that there are $6.022\, \times \,{10^{23}}$ amount of particles in one mole of any atom. To solve for $6.22\,moles$ you have to multiply the amount with Avogadro number. For this type of conversion, always remember that any element or compound will have Avogadro amount of particles, atoms, molecules etc.

Complete step-by-step answer:
We know that lithium is a first group element having atomic number of $3$ , it means that the number of electrons and protons are three in number. When it comes to the amount of particles that any compound has, we use the Avogadro number to convert moles into atoms, or atoms into moles.

If we say that one mole of lithium contains $6.022\, \times \,{10^{23}}$ atoms, then these amounts consist of one mole. For calculating the amount of atoms in a particular number of moles we have to multiply it with that number. Suppose you have a box, in that box you have three balls now for calculating the number of balls in four same types of boxes, you have to multiply three balls with four boxes to get the total number.

Similarly here, we have $6.022\, \times \,{10^{23}}$ atoms in one mole
$1\,mole = \,6.022\, \times \,{10^{23}}\,atoms$
Number of particles in $6.22\,moles$ = $6.022\, \times \,{10^{23}}\, \times \,6.22\,\,atoms$
Number of particles in $6.22\,moles$ = $37.45\,\, \times \,{10^{23}}\,atoms\,$
Number of particles in $6.22\,moles$ = $3.745\,\, \times \,{10^{24}}\,atoms\,$
Thus we get to know after calculating that $6.22\,moles$ contains $3.745\,\, \times \,{10^{24}}\,atoms\,$

Note: You have to understand this concept on the basis of moles and particles, where particles can be atoms, molecules etc. Above we have taken an example where the total numbers of balls are equal to the multiplication of balls in one box with the number of boxes. You can change the amount by shifting the decimal in left and right hand direction.