Question

How many atoms of calcium will be deposited from a solution of $AgNO_{3}$ by a current of 25 milliamperes flowing for 60 seconds.

• A. $AgNO_{3}$
• B. $H_{2}$
• C. $NO_{3}^{-}$
• D. $OH^{-}$

Answer 1

Answer: (A)

$AgNO_{3}$

Answer 2

Quantity of electricity passed = $\frac{25}{1000} \times 60 = 1.5$

$2F = 2 \times 96500C$ deposit $Ca = 1mole$

1.5 C will deposit $Ca = \frac{1}{2 \times 96500} \times 1.5mole$

$= \frac{1}{2 \times 96500} \times 1.5 \times 6.023 \times 10^{23}$ atom $= 4.68 \times 10^{18}$.