Question

How many atoms are represented in this formula $Ni{\left( {{C_2}{H_3}{O_2}} \right)_4}$?

Answer 1

We must need to know that a coordination complex comprises a central metal atom, and is known as the coordination center, and an encompassing exhibit of bound particles or particles, that are thus known as ligands or complexing agents. Many metal-containing mixes, particularly those of change metals, are coordination complexes. A coordination complex whose middle is a metal iota is known as a metal complex of d square components.

Complete step by step answer:
The formula of the compound is $Ni{\left( {{C_2}{H_3}{O_2}} \right)_4}$.
The number of atoms in the formula is twenty nine. There is one nickel atom and (C_2H_3O_2) all together has seven atoms and multiply by 4 thus totally 28. $1 + \left( 7 \right)4 = 29$

Additional information:
The particles encompassing the central metal atom are called ligands. Ligands are named L or X, contingent upon the number of electrons they accommodate the connection among ligands and focal particles. L ligands give two electrons from a solitary electron pair, bringing about a facilitated covalent bond. X ligands give one electron, with the focal molecule giving the other electron, consequently framing a customary covalent bond. The ligands are supposed to be facilitated to the iota. For alkenes, the pi bonds can organize to metal molecules.

Note: Nickel (II) acetate derivation is the name for the coordination complex $Ni{\left( {{C_2}{H_3}{O_2}} \right)_4}.x{H_2}O$ where x can be 0, 2, and 4. The green trihydrates Nickel (II) acetate is generally normal. It is utilized for electroplating. The green trihydrates has been appeared by X-beam crystallography to embrace an octahedral structure, the focal nickel place being composed by four water particles and two acetic acid derivation ligands. It might be dried out in vacuum, by response with acidic anhydride, or by heat.