Question
Question: how many atoms are present in \[1.55mol\] of sodium?...
how many atoms are present in 1.55mol of sodium?
Solution
We identify that one mole of all chemicals comprises Avogadro number of atoms in it.
One mole of a chemical = Avogadro number of atoms.
The symbol to symbolize Avogadro number is Na.
The value of Avogadro number 6.023×1023atoms .
Complete step by step answer:
In the question it is specified that we have to analyze the number of atoms in 1.55mol of sodium.
The chemical sign used to represent the sodium is Na and sodium belongs to s-block.
We identify that 1mole of sodium holds Avogadro number of atoms.
One mole of sodium 6.023×1023atoms
But then we have to discover the number of atoms in 1.55mol of sodium.
Then 1.55mol of sodium
1.55mol Na 1mol6.022×1023=9.33×1023 atoms of Na
Then, 1.55mol of sodium (Na) contains 9.33×1023 atoms in it.
Additional information:
The term Avogadro number was presented by Perrin. a French physicist.
Avogadro number is the proportionality factor that gives the evidence about the number of atoms in the specified amount of sample or chemical.
Occasionally Avogadro numbers are called Avogadro constants.
Sodium is important for many dissimilar functions of the human body. E.g., it helps cells to convey nerve signals and regulate water echelons in tissues and blood. Sodium is the sixth most communal element on Earth, and marks up 2.6% of the Earth's crust. The most communal compound is sodium chloride.
Note: Avogadro number is the proportion of charge on a mole of electrons to the charge on a on its own electron .There is no relation among molecular weight of the substance and Avogadro number. Avogadro number is going to be determined by the number of moles of the biochemical.