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Question

Question: How many 4-digit numbers can be formed from digits 1, 1, 2, 2, 3, 3, 4, 4, 5, 5....

How many 4-digit numbers can be formed from digits 1, 1, 2, 2, 3, 3, 4, 4, 5, 5.

Explanation

Solution

In the above question we need to find the number of ways to form 44-digit numbers. If all four digits are different, we use 5P4^5{P_4}. If there is one repeated digit, there are 55 ways to choose which digit is repeated. Then there are 4C2=6^4{C_2} = 6 ways to place the repeated digit and 4P2^4{P_2} = 12 ways to place the non – repeated digits. And similarly, we arrange numbers when there are two repeated digits.

Complete step by step solution:
According to the question, we have to from 44-digit number from digits 1,1,2,2,3,3,4,4,5,51, 1, 2, 2, 3, 3, 4, 4, 5, 5.
We can form 44-digit number in three ways –
When all the four digits are different, then the number of 4-digit number can be formed is = 5P4^5{P_4}
=5!1!= \dfrac{{5!}}{{1!}}
=5×4×3×2×11= \dfrac{{5 \times 4 \times 3 \times 2 \times 1}}{1}
=120= 120ways.
When two digits are same and another two digits are different, then the number of 4-digit numbers can be formed is =5C1×4C2×4P2^5{C_1}{ \times ^4}{C_2}{ \times ^4}{P_2}
=5!4!×1!×4!2!×2!×4!2!= \dfrac{{5!}}{{4! \times 1!}} \times \dfrac{{4!}}{{2! \times 2!}} \times \dfrac{{4!}}{{2!}}
=5×4!4!×1×4×3×2!2!×2×1×4×3×2!2!= \dfrac{{5 \times 4!}}{{4! \times 1}} \times \dfrac{{4 \times 3 \times 2!}}{{2! \times 2 \times 1}} \times \dfrac{{4 \times 3 \times 2!}}{{2!}}
=5×6×12= 5 \times 6 \times 12
=360= 360 ways
When there are two repeated digits, then the number of 4-digit numbers can be formed is = 5C2^5{C_2}
=5!3!×2!= \dfrac{{5!}}{{3! \times 2!}}
=5×4×3!3!×2×1= \dfrac{{5 \times 4 \times 3!}}{{3! \times 2 \times 1}}
=10= 10
There are 66 ways to place the first repeated digit and 11 way to place the second repeated digit.
Thus, we have;
Total number of ways when there are two repeated digits are=10×6×1=60= 10 \times 6 \times 1 = 60ways
Total number of ways to form 4-digit numbers from given digits are=120+360+60 = 120 + 360 + 60
=580= 580 ways.

\therefore Total number of ways to form 4-digit numbers from given digits = 580.

Note:
In these types of questions use the permutation concept. Permutations are for lists where order matters and combinations are for groups where order doesn’t matter.