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Question: How is \(MgS{{O}_{4}}\) produced from \(MgC{{O}_{3}}\)? (A) \(MgC{{O}_{3}}\)+ S (B) \(MgC{{O}_{3...

How is MgSO4MgS{{O}_{4}} produced from MgCO3MgC{{O}_{3}}?
(A) MgCO3MgC{{O}_{3}}+ S
(B) MgCO3MgC{{O}_{3}}+ SO2S{{O}_{2}}
(C) MgCO3MgC{{O}_{3}}+ SO3S{{O}_{3}}
(D) MgCO3MgC{{O}_{3}}+ H2SO4{{H}_{2}}S{{O}_{4}}

Explanation

Solution

Metals, metal oxides, metal carbonate and metal hydroxides react with acids to produce the respective salts. For example, if we want to prepare metal chloride then allow metal, metal oxides, metal carbonate or metal hydroxide to hydrochloric acid. Similarly use sulphuric acid for sulphate yield.

Complete answer:
Magnesium sulphate is a fertilizer, commonly known as Epsom salt. It is a source of magnesium and Sulphur for plants. It can be prepared from the naturally occurring magnesium minerals like Kieserite (MgSO4.H2OMgS{{O}_{4}}.{{H}_{2}}O) or epsomite (MgSO4.7H2OMgS{{O}_{4}}.7{{H}_{2}}O). For industrial production purpose magnesium oxide (MgO), magnesium hydroxide (Mg(OH)2Mg{{(OH)}_{2}}) or magnesium carbonate (MgCO3MgC{{O}_{3}}) are used.
In laboratory, magnesium sulphate can be prepared by direct dissolving magnesium, magnesium oxide (MgO), magnesium hydroxide Mg(OH)2Mg{{(OH)}_{2}}or magnesium carbonate (MgCO3MgC{{O}_{3}}) in dilute sulphuric acid (H2SO4{{H}_{2}}S{{O}_{4}}).MgSO4.7H2OMgS{{O}_{4}}.7{{H}_{2}}Ocrystallizes the evaporation of the so prepared above solution. On overeating of the crystals ofMgSO4.7H2OMgS{{O}_{4}}.7{{H}_{2}}Othe hydrated molecule becomes anhydrous.
Chemical reaction for the preparation of MgSO4MgS{{O}_{4}} from different compounds are:
From magnesium: Mg+H2SO4 MgSO4+H2 Mg+{{H}_{2}}S{{O}_{4}}\to \text{ }MgS{{O}_{4}}+{{H}_{\begin{matrix} 2 \\\ \end{matrix}}}
From magnesium oxide: MgO+H2SO4 MgSO4+H2OMgO+{{H}_{2}}S{{O}_{4}}\to \text{ }MgS{{O}_{4}}+{{H}_{2}}O
From magnesium hydroxide: Mg(OH)2+H2SO4 MgSO4+2H2OMg{{(OH)}_{2}}+{{H}_{2}}S{{O}_{4}}\to \text{ }MgS{{O}_{4}}+2{{H}_{2}}O
From magnesium carbonate: MgCO3+H2SO4  MgSO4+H2O+CO2MgC{{O}_{3}}+{{H}_{2}}S{{O}_{4}}\to \ \text{ }MgS{{O}_{4}}+{{H}_{2}}O+C{{O}_{2}}
Among the given options we just check the reaction of magnesium carbonate to produce magnesium sulphate. So, the option (d) is correct as in it magnesium carbonate is a reaction with sulphuric acid.

Note:
Direct reaction with Sulphur, Sulphur di or tri oxide gases don’t give magnesium sulphate. We need acids to provide the anion of our interest to obtain the desired product. In this case it is magnesium sulphate.