Question

How does the electric field relate to voltage?

Answer 1

The electric field is by definition the force per unit charge so that copying the field times the plate division gives the work per unit charge, which is by definition the change in voltage. Electric Potential difference, otherwise called voltage, is the outside work expected to carry a charge starting with one area then onto the next area in an electric field. Electric potential contrast is the difference in potential energy experienced by a test charge that has an estimation of $+ 1$.

Complete answer:
Voltage is potential energy per unit charge, and an electric field is a power per unit charge. We can in this way relate voltage and field in the event that we start from the connection between possible energy and power,
$\Rightarrow \Delta V = - Ed$
All in all, the distinction in voltage between two focuses rises to the electric field strength duplicated by the distance between them. The translation is that a solid electric field is a district of the room where the voltage is quickly evolving. By similarity, a lofty height is a spot on the guide where the elevation is quickly evolving.

Note: Electric field and potential in one measurement: The presence of an electric field around the static point charge makes an expected distinction, causing the test charge to encounter power and move.
The electric field resembles some other vector field—it applies a power dependent on an improvement, and has units of power time’s backward boost. On account of an electric field, the upgrade is a charge, and hence the units are $N{C^{ - 1}}$. As such, the electric field is a proportion of power for each unit charge.
The electric potential at a point is the remainder of the likely energy of any charged molecule at that area isolated by the charge of that molecule. Its units are $J{C^{ - 1}}$. Hence, the electric potential is a proportion of energy for every unit charge.