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Question

Question: How does \[\sin x=0\] equals \[\pi \]?...

How does sinx=0\sin x=0 equals π\pi ?

Explanation

Solution

In this problem, we have to find how sinx=0\sin x=0 equals π\pi . We should always know that the sine value is always equal to zero for every multiple of π\pi , where π\pi radians is equal to 180{{180}^{\circ }}. We can now draw a graph with a sine curve to see the value of sine for π\pi .

Complete step by step answer:
We know that the given trigonometric function given is sine.
We should always remember that the sine value is always equal to zero for every multiple of π\pi , where π\pi radians is equal to 180{{180}^{\circ }}.
We can now draw a graph with a sine curve to see the value of sine for π\pi .


We can now see that the sine curve touches the line at 0 in every multiple of π\pi .
We can now write it as,
sinx=0x=k×π\Rightarrow \sin x=0\to x=k\times \pi
Where k is any whole number.
Therefore, we can summarize that every multiple of π\pi for the sine function is always equal to zero.

Note: Students should also remember that π\pi radians is equal to 180{{180}^{\circ }}. We should also know that the sine function goes from 0 to 90=π2{{90}^{\circ }}=\dfrac{\pi }{2}and then back to 0 to 180=π{{180}^{\circ }}=\pi , and when we come down to -1 to 270=3π2{{270}^{\circ }}=\dfrac{3\pi }{2} and when we go up to 0 again at 360=2π{{360}^{\circ }}=2\pi , therefore, it will be 0 at every multiple of π\pi . We should also concentrate in the graph part while drawing the sine curve.