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Question: How does acid and bases affect \(pH\)?...

How does acid and bases affect pHpH?

Explanation

Solution

Use relation of pHpH and H+{H^ + }to find the effect of acids and bases. Acids will increase the concentration of H+{H^ + } ions while on the other hand bases decreases H+{H^ + } concentration. A decrease in concentration of H+{H^ + } ion will increase the pHpH and if there is an increase in H+{H^ + } concentration the pHpH decreases.

Complete answer:
Both acidity and basicity is termed according to the concentration of hydrogen ions in their solutions. There are in total three theories which give the different definitions of acids and bases. So if we consider the first theory it will suggest that an acid is a solution which gives H+{H^ + } ions in solution or increases the concentration of these ions. While on the other we can say bases are the substance which decrease the concentration of H+{H^ + } or increase the concentration of OH{}^ - OH ions.
Now we get what acids and bases and how there is an increase in concentrations of hydrogen ion. Now let’s see what will happen if these ions get increased or decrease on pHpH .
We know from our classes that pHpH and H+{H^ + } are connected by a formula, which we can write it as pH=log[H+]pH = - \log \left[ {{H^ + }} \right] , here if concentration of H+{H^ + } increases then overall value get negative and at last pHpH get decrease. On the other hand, if the concentration of H+{H^ + } decreases having a negative value, at the end the overall value increases and we get a positive value at last forpHpH.
Now let’s understand this concept by taking an example of hydrochloric acid HClHCl and sodium hydroxide NaOHNaOH. Suppose we take water in a beaker and then we are adding HClHCl drop by drop, by this drop by drop concentration of H+{H^ + } increases in the beaker because acid gives H+{H^ + } in the solution thus by applying this relation pH=log[H+]pH = - \log \left[ {{H^ + }} \right] overall pHpH get decrease. In the scale of 11 to 1414 acid gets pHpHbelow 66 . On the other hand if we take NaOHNaOH in the beaker and put it drop by drop, it will give hydroxide ions in the solution OH{}^ - OH or we can say concentration of OH{}^ - OH increases and concentration of H+{H^ + } decreases. By the above relation we now get it that the overall pHpHincreases and gave a positive value, so in case of bases their pHpH remain greater than 77 in scale of 1141 - 14

Note: We should keep in mind that while putting the values in the relation of pHpH and H+{H^ + } concentration which is pH=log[H+]pH = - \log \left[ {{H^ + }} \right] , always put concentration in units of (M) molarity. Calculate the value of (log)(\log ) not (ln)(\ln ) because we always have confusion between the two (log)(\log ) is in base (10)(10) while (ln)(\ln ) is in base (e)(e).