Question

How do you write $y = 3x - 8$ in standard form?

Answer 1

Hint : To solve the given question we have to use a formula of straight line which is defined $Ax + By = C$
While applying this formula in question we have to keep one thing in mind that $A$ , $B$ and $C$ are constants in this formula.

Complete step-by-step answer :
If we clearly observe the question we get that there is an equation of straight line it which is
$y = 3x - 8$
To write an equation in standard form we simply have to separate $x$ & $y$ variables from constant $C$ .
If we compare equation (1) given in hint with equation (2) given in question we come on the conclusion that
$Ax = 3x$
$By = y$
And $C = - 8$
So, to write this straight line equation in standard form we have to assign it as,
Now, we have to transfer $3x$ from right hand side to left hand side.
After transferring it we get,
$- 3x + y = - 8$
So, equation (3) which is $- 3x + y = - 8$ is the same type of equation which is given in equation (1) i.e. $Ax + By = C$ .
So, the standard form of equation (2) i.e. $y = 3x - 8$ is equation (3) i.e. $- 3x + y = - 8$ OR
$3x - y = 8$
So, the correct answer is “ $3x - y = 8$ ”.

Note : To solve these types of questions, we should have some knowledge of the standard form of straight line and some basic rules of transferring in the left hand side and right hand side. We tend to write the first term positive and change the signs of other terms accordingly.