Question
Question: How do you write the standard form of the equation given \[\left( {1,2} \right)\] slope 7?...
How do you write the standard form of the equation given (1,2) slope 7?
Solution
Hint : Point-slope is the general form y−y1=m(x−x1) for linear equations. It emphasizes the slope of the line and a point on the line i.e., not the y-intercept. Hence, to write the standard form of the equation of the given points and the slope, use the point-slope form formula by substituting the given values and then apply in its standard form as Ax+By=C .
Formula used:
y−y1=m(x−x1)
x1 is the x-coordinate of the point.
y1 is the y-coordinate of the point.
m is the slope of a line.
x, y are the variables.
Complete step-by-step answer :
Given,
Equation of a line passes through the points: (x1,y1)=(1,2)
Slope: m=7
We know that, the equation in point-slope form formula is given as:
y−y1=m(x−x1) …………………… 1
As we have the values of x1,y1,m , hence substitute these values in equation 1 as:
y−y1=m(x−x1)
⇒y−2=7(x−1) ………………. 2
Now, distribute and simplify the terms of equation 2:
⇒y−2=7x−7
Now add 2 on both the sides of the equation:
y−2+2=7x−7+2
As, we know that +2 and -2 implies to zero, hence we get:
⇒y=7x−7+2
Simplify the terms:
⇒y=7x−5
Hence, move y over by subtracting it and move 5 over by adding it, hence now you have your Equation in Standard Form as: Ax+By=C
y=7x−5
⇒7x−y=5
Therefore, the standard form of the equation is:
7x−y=5
So, the correct answer is “ 7x−y=5 ”.
Note : An equation of a line can be expressed in many ways as: Slope Intercept, Standard or Point-Slope. The equation of a straight line of the form y−y1=m(x−x1) is called its point-slope form. The equation of a straight line of the form y=mx+b is called its slope-intercept form. Hence, these are key points to know while solving the equation of a line.