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Question: How do you write the standard form of the equation given \[\left( {1,2} \right)\] slope 7?...

How do you write the standard form of the equation given (1,2)\left( {1,2} \right) slope 7?

Explanation

Solution

Hint : Point-slope is the general form yy1=m(xx1)y - {y_1} = m\left( {x - {x_1}} \right) for linear equations. It emphasizes the slope of the line and a point on the line i.e., not the y-intercept. Hence, to write the standard form of the equation of the given points and the slope, use the point-slope form formula by substituting the given values and then apply in its standard form as Ax+By=CAx + By = C .
Formula used:
yy1=m(xx1)y - {y_1} = m\left( {x - {x_1}} \right)
x1{x_1} is the x-coordinate of the point.
y1{y_1} is the y-coordinate of the point.
m is the slope of a line.
x, y are the variables.

Complete step-by-step answer :
Given,
Equation of a line passes through the points: (x1,y1)=(1,2)\left( {{x_1},{y_1}} \right) = \left( {1,2} \right)
Slope: m=7m = 7
We know that, the equation in point-slope form formula is given as:
yy1=m(xx1)y - {y_1} = m\left( {x - {x_1}} \right) …………………… 1
As we have the values of x1,y1,m{x_1},{y_1},m , hence substitute these values in equation 1 as:
yy1=m(xx1)y - {y_1} = m\left( {x - {x_1}} \right)
y2=7(x1)\Rightarrow y - 2 = 7\left( {x - 1} \right) ………………. 2
Now, distribute and simplify the terms of equation 2:
y2=7x7\Rightarrow y - 2 = 7x - 7
Now add 2 on both the sides of the equation:
y2+2=7x7+2y - 2 + 2 = 7x - 7 + 2
As, we know that +2 and -2 implies to zero, hence we get:
y=7x7+2\Rightarrow y = 7x - 7 + 2
Simplify the terms:
y=7x5\Rightarrow y = 7x - 5
Hence, move y over by subtracting it and move 5 over by adding it, hence now you have your Equation in Standard Form as: Ax+By=CAx + By = C
y=7x5y = 7x - 5
7xy=5\Rightarrow 7x - y = 5
Therefore, the standard form of the equation is:
7xy=57x - y = 5
So, the correct answer is “ 7xy=57x - y = 5 ”.

Note : An equation of a line can be expressed in many ways as: Slope Intercept, Standard or Point-Slope. The equation of a straight line of the form yy1=m(xx1)y - {y_1} = m\left( {x - {x_1}} \right) is called its point-slope form. The equation of a straight line of the form y=mx+by = mx + b is called its slope-intercept form. Hence, these are key points to know while solving the equation of a line.