Question
Question: How do you write the standard form of equation given\[\left( {3,5} \right)\] and slope\[\dfrac{5}{3}...
How do you write the standard form of equation given(3,5) and slope35 ?
Solution
The standard form for linear equations in two variables is Ax+By=C where A, B and C are real numbers and both A and B are non-zero. In general, the slope intercept form formula is y=mx+b where, m is the slope and b is the y-intercept. We need to find the standard form of the equation of a line through the given point with a given slope.
Complete step by step answer:
Given points are (x1,y1)=(3,5)with the slopem=35. Here, we will use the slope point formula as we are given a point and a slope of the line.
y2−y1=m(x2−x1)
Let, (x2,y2)=(x,y)
Substituting the values in the above formula, we get,
⇒y−5=35(x−3)
Taking LCM as 3on both the side, we get,
⇒y(3)−5(3)=5(x−3)
Removing the brackets, we get,
⇒3y−15=5x−15
By using transposing in this above equation, we get,
⇒3y−5x=−15+15
⇒3y−5x=0
Again by using transposition, we move all from LHS to RHS, we get,
⇒0=+5x−3y
Rearranging the above equation, we get,
⇒5x−3y=0
Thus, the equation in slope intercept form is :
5x−3y=0
⇒5x=3y
⇒3y=5x
∴y=35x
Hence, the above equation can be rewritten in the standard form as −5x+3y=0 for the given point (3,5) and slope 35.
Note: The slope-intercept form is given as y=mx+b where m is the slope and b is the y-intercept when x=0 or at point (0,b). Since we used the coordinates of one known point and the slope to write this form of equation it is called the point-slope form. Also, since the slope of a vertical line is undefined you can't write the equation of a vertical line using either the slope-intercept form or the point-slope form. But you can express it using the standard form. We can also use the graph to show the line.