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Question

Question: How do you write the polar equation \(\theta = \dfrac{\pi }{3}\) in rectangular form?...

How do you write the polar equation θ=π3\theta = \dfrac{\pi }{3} in rectangular form?

Explanation

Solution

Hint : We are given a polar equation that we have to convert into a rectangular form. We will express both the left-hand side and the right-hand side of the given equation in terms of x and y so that we get all the quantities in terms of x and y and we get the rectangular form of the given polar equation by further solving the equation.

Complete step-by-step answer :
A right-angled triangle is formed by x, y and r, where r is the hypotenuse, x is the base and y is the height of the triangle, so by Pythagoras theorem, we have - x2+y2=r2{x^2} + {y^2} = {r^2} and by looking at the components of r - x=rcosθandy=rsinθx = r\cos \theta \,and\,y = r\sin \theta and by trigonometry or by dividing the components we have - tanθ=yx\tan \theta = \dfrac{y}{x} .
We are given θ=π3\theta = \dfrac{\pi }{3}
We know –
tanθ=yx θ=tan1yx   \tan \theta = \dfrac{y}{x} \\\ \Rightarrow \theta = {\tan ^{ - 1}}\dfrac{y}{x} \;
Using this value in the given equation –
tan1yx=π3 yx=tanπ3 yx=3 y=3x   {\tan ^{ - 1}}\dfrac{y}{x} = \dfrac{\pi }{3} \\\ \Rightarrow \dfrac{y}{x} = \tan \dfrac{\pi }{3} \\\ \Rightarrow \dfrac{y}{x} = \sqrt 3 \\\ \Rightarrow y = \sqrt 3 x \;
Hence, the polar equation θ=π3\theta = \dfrac{\pi }{3} in rectangular form is y=3xy = \sqrt 3 x .
So, the correct answer is “y=3xy = \sqrt 3 x”.

Note : The most commonly used coordinate system is the rectangular coordinate system that is also called the cartesian system and it is of the form (x,y)(x,y) where x is the distance of this point from the y-axis and y is the distance of the point from the x-axis. The points of the form (r,θ)(r,\theta ) are polar coordinate systems, where r is the distance of the point from the origin and θ\theta is the counter-clockwise angle between the line joining the point and the origin, and the x-axis.