Question

How do you write the noble gas electron configuration for magnesium?

Answer 1

You had an incredible dinner yet can't place another chomp in your mouth in light of the fact that there is a bad situation for it to go. The honorable gases have a similar issue - there is no space for additional electrons in their external shells. They are totally full and can't deal with it any longer.

Complete answer:
Mg is $1{s^2}2{s^2}2{p^6}3{s^2}$ its Noble gas shorthand is $[Ne]3{s^{^2}}$
There are two standards to remember, at whatever point you are attempting to sort out the electron arrangement of any ground-state molecule:
You need to follow the Aufbau guideline, which expresses that electrons populate the nuclear orbitals arranged at the most minimal energy first. There are two sections to the Ababa rule. The first is Klechkowsky's standard, which expresses that electrons should be doled out arranged by expanding estimation of$\left( {n + l} \right)$. If there should arise an occurrence of a tie, the second bit of the Ababa guideline.
1s
2s2p
3s3p3d
4s4p4d4f
5s5p5d5f
6s6p6d
7s7p

The order would be $\text{1s 2s 2p 3s 3p 4s 3d 4p 5s 4d 5p 6s 4f …}$
Obviously, on the off chance that you have the occasional table of components with you, you can follow your way across periods to discover the electron arrangement of Magnesium. Note that primary gathering components hold a similar head quantum number while progress metals must be considered as $\left( {n - 1} \right)d$ an internal change metals must be viewed as (n−2)f while getting across the occasional table of components.

Note: To compose the Mg electron arrangement, we first need to know the quantity of electrons for the Mg iota (there are 12 electrons). At the point when we compose the design we'll place each of the 12 electrons in orbitals around the core of the Magnesium molecule.