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Question: How do you write the exponent for the expression \(6\times 6\times 6\times 6\times 6\)?...

How do you write the exponent for the expression 6×6×6×6×66\times 6\times 6\times 6\times 6?

Explanation

Solution

We first explain the process of exponents and indices. We find the general form. Then we explain the different binary operations on exponents. Finally, we find the indices number for 6×6×6×6×66\times 6\times 6\times 6\times 6 and express it in that form.

Complete step by step solution:
We know the exponent form of the number aa with the exponent being nn can be expressed as
an{{a}^{n}}.

The simplified form of the expression an{{a}^{n}} can be written as the multiplied form of number
aa of n-times.

Therefore, an=a×a×a×....×a×antimes{{a}^{n}}=\underbrace{a\times a\times a\times ....\times a\times a}_{n-times}.

The value of nn can be any number belonging to the domain of real numbers.
Similarly, the value of aa can be any number belonging to the domain of real numbers.

In case the value of nn becomes negative, the value of the exponent takes its inverse value.

The formula to express the form is an=1an,nR+{{a}^{-n}}=\dfrac{1}{{{a}^{n}}},n\in {{\mathbb{R}}^{+}}.

The multiplication of these exponents works as the addition of those indices.

For example, we take two exponential expressions where the exponents are mm and nn.

Let the numbers be am{{a}^{m}} and an{{a}^{n}}. We take multiplication of these numbers.

The indices get added. So, am×an=am+n{{a}^{m}}\times {{a}^{n}}={{a}^{m+n}}.

The division works in an almost similar way. The indices get subtracted. So,
aman=amn\dfrac{{{a}^{m}}}{{{a}^{n}}}={{a}^{m-n}}.

For our given expression, we need to express 6×6×6×6×66\times 6\times 6\times 6\times 6 in its exponential way.

There are five sixes in multiplied form. The indices value will be 5. The indices will be for the number 6.

So, expressing in exponent form we get 6×6×6×6×6=656\times 6\times 6\times 6\times 6={{6}^{5}}.

Note: The addition and subtraction for exponents works for taking common terms out depending on the values of the indices. For numbers am{{a}^{m}} and an{{a}^{n}}, we have am±an=am(1±anm){{a}^{m}}\pm {{a}^{n}}={{a}^{m}}\left( 1\pm {{a}^{n-m}} \right).the relation is independent of the values of mm and nn.