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Question: How do you write the equation of the line given the slope \(2\) , \(y\) -intercept \(\left( 0,9 \rig...

How do you write the equation of the line given the slope 22 , yy -intercept (0,9)\left( 0,9 \right) ?

Explanation

Solution

In problems like this it is necessary to know the slope and yy -intercept of the straight line to write an equation of it. We will get the equation in its slope intercept form by using the values of the slope and yy -intercept. For that we will take the general equation of a straight line in the slope intercept form and putting the given values in that equation we will get the equation of the straight line.

Complete step by step answer:
To get the equation of a straight line in the slope intercept form it is necessary to know the values of the slope and the y-intercept. In this question we are given the value of the slope of the straight line as 2 and the line passes through the point (0,9)\left( 0,9 \right) .
As the straight line passes through (0,9)\left( 0,9 \right) we can say the yy -intercept of the line is 99 as the line cuts the yy axis at a distance of 99 units from the origin.
Now, we take the general equation of the straight line in the slope intercept form as
y=mx+cy=mx+c
Here, mm is the slope and cc is the yy -intercept of the straight line
Hence, for this problem we can write m=2m=2 and c=9c=9
Now, we substitute the above values of the slope and yy -intercept in the general equation of the straight line as shown below
y=2x+9\Rightarrow y=2x+9

Therefore, we can conclude that the equation of the straight line is y=2x+9y=2x+9 .

Note: We must keep in mind that we have taken the value of cc as 99 because the xx coordinate of the given point is zero. If we were given a point other than that we should have put that point in the equation of the line to find the value of cc . Also, we must put the proper values in the equation that are given, as inaccurate values will lead to wrong answers.