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Question: How do you write the equation in slope intercept form given \(( - 5,0)\) and \((3,3)\)?...

How do you write the equation in slope intercept form given (5,0)( - 5,0) and (3,3)(3,3)?

Explanation

Solution

In this question, we need to find the equation of a line in slope intercept form. Firstly, we need to find the slope of the given line using the given points. To find the slope we use the formula m=y2y1x2x1m = \dfrac{{{y_2} - {y_1}}}{{{x_2} - {x_1}}}. After finding the slope of the line, we substitute in the equation of a line given by yy1=m(xx1)y - {y_1} = m(x - {x_1}) and find the equation of a given line.

Complete step by step answer:
Here we are given the two points (5,0)( - 5,0) and (3,3)(3,3).
We are asked to find the equation of a line which passes through the above given points.
Now we represent the given two points as,
(x1,y1)=(5,0)({x_1},{y_1}) = ( - 5,0)
(x2,y2)=(3,3)({x_2},{y_2}) = (3,3)
Firstly, we need to find out the slope of the given line.
The slope of any given line is found using the formula, m=y2y1x2x1m = \dfrac{{{y_2} - {y_1}}}{{{x_2} - {x_1}}}
where mm represents the slope of the line.
Now substituting the values of the variable in the above formula we get,
m=303(5)m = \dfrac{{3 - 0}}{{3 - ( - 5)}}
m=33+5\Rightarrow m = \dfrac{3}{{3 + 5}}
m=38\Rightarrow m = \dfrac{3}{8}
Now we have found the value of the slope of a given line.
We place this value in the equation of a line to obtain the required equation of a line formed by the two points.
The formula to find the equation of a line is given by,
yy1=m(xx1)y - {y_1} = m(x - {x_1})
where x,x, yy are constants and y1,{y_1}, x1{x_1}are variables.
Substituting the values we get,
y0=38(x(5))\Rightarrow y - 0 = \dfrac{3}{8}(x - ( - 5))
Solving it further we get,
y=38(x+5)\Rightarrow y = \dfrac{3}{8}(x + 5)
y=38x+38(5)\Rightarrow y = \dfrac{3}{8}x + \dfrac{3}{8}(5)
y=38x+158\Rightarrow y = \dfrac{3}{8}x + \dfrac{{15}}{8}
Now this is in the form of y=mx+cy = mx + c which is a standard slope intercept form.
Hence comparing the above obtained equation with the standard slope intercept form we get,
m=38m = \dfrac{3}{8} and c=158c = \dfrac{{15}}{8} which are the slope and y-intercept of the given line.

Hence, the equation of a line with the given points (5,0)( - 5,0) and (3,3)(3,3) in slope intercept form is given by y=38x+158y = \dfrac{3}{8}x + \dfrac{{15}}{8}.

Note: The slope of a line is the steepness of a line in a horizontal or vertical direction. The slope of a line can be calculated by taking the ratio of the change in vertical dimensions upon the change in horizontal dimensions.
i.e. slope, m=y2y1x2x1m = \dfrac{{{y_2} - {y_1}}}{{{x_2} - {x_1}}}
Also remember the formula to find the equation of a line given by yy1=m(xx1)y - {y_1} = m(x - {x_1}) and substitute the given values.
The standard slope intercept form of a straight line is given by y=mx+cy = mx + c, where mm is the slope of the line and cc is the y-intercept