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Question

Question: How do you write the equation given slope \(2\) and passes through \(( - 2, - 5)?\)...

How do you write the equation given slope 22 and passes through (2,5)?( - 2, - 5)?

Explanation

Solution

As we know that the given equation that can be formed is a linear equation in two variables. An equation of the form px+qy=rpx + qy = r, where p,qp,q and rr are real numbers and the variables pp and qq are not equivalent to zero, is called linear equation in two variables. The slope intercept form of a linear equation has the following term where the equation is solved for yy in terms of x:y=a+bxx:y = a + bx, bb is the slope and aa is a constant term.

Complete step by step solution:
We will rewrite the standard form of linear equation: ax+by=cax + by = c. The slope intercept form of the equation is y=mx+by = mx + b.
Here we have x=2x = - 2 and y=5y = - 5, the slope i.e. m=2m = 2. Now we substitute all the values in the equation y=mx+by = mx + b, we get 5=2×2+b - 5 = 2 \times - 2 + b, on further solving we have 5=4+bb=5+4=1 - 5 = - 4 + b \Rightarrow b = - 5 + 4 = 1.
So the given equation is 2xy1=02x - y - 1 = 0.

Hence the slope intercept form of the above equation is 2xy1=02x - y - 1 = 0.

Note:
We know that the formula of slope intercept form is y=mx+by = mx + b where yyis the “y” coordinate, mmis the slope, xxis the “x” coordinate and bbis the ‘y’ intercept. We can use this form of linear equation to draw the graph of the given equation on the “x” and “y” coordinate plane. We should keep in mind that the conversion of the equation of the line to slope intercept form is done by simple manipulation. YYintercept of the line is the point where the line cuts the ‘y’ axis and the slope is tan of the angle that is made by the line on the x- axis.