Question

How do you write slope: $1.5$, y-intercept: $-1$ in slope intercept form?

Answer 1

In the above question, we have been given the information of a line whose slope is given to be equal to $1.5$, and the y-intercept is given to be equal to $-1$. And we have been asked to write the equation of the line in the slope intercept form. The slope intercept form of the equation of a line is given as $y=mx+c$ where m is equal to the slope of the line and c is equal to the y-intercept for the line. Therefore, on substituting $m=1.5$ and $c=-1$ into the equation $y=mx+c$, we will obtain the required slope intercept form of the equation for the given line.

Complete step by step answer:
According to the question, we have been given the values of the slope and the y-intercept. We know that these terms are defined for a line. Therefore, we have been given the information for a straight line.
Now, the slope is given to be equal to $1.5$, which means that we can write
$\Rightarrow m=1.5........\left( i \right)$
Also, the y-intercept is given to be equal to $-1$, which means that we can write
$\Rightarrow c=-1........\left( ii \right)$
Now, we are asked to write the equation for the line in the slope intercept form. We know that the slope intercept form of the equation of a line is given by
$\Rightarrow y=mx+c$
On substituting the equations (i) and (ii) into the above equation, we finally get
$\Rightarrow y=1.5x-1$
The graph of the straight line represented by the above equation is given below.

Hence, we have written the slope intercept form of the equation for the given line as $y=1.5x-1$.

Note: For solving the questions of these types, we must keep in mind all of the standard forms of the equation of a straight line. The different forms of the equation are the two point form, the point slope form, the intercept form etc.