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Question

Question: How do you write \[{{e}^{3}}=20.0855\] in logarithmic form?...

How do you write e3=20.0855{{e}^{3}}=20.0855 in logarithmic form?

Explanation

Solution

In this problem, we have to convert the given exponential form into its logarithmic form. We can first take log on both the left-hand side and the right-hand side to remove the exponent form and to write in logarithmic form. We can then use the logarithmic formula or identity lne=1\ln e=1 on the left-hand side, we will get the logarithmic form.

Complete step-by-step solution:
We know that the given exponential form is,
e3=20.0855{{e}^{3}}=20.0855
We know that a natural exponential equation in logarithmic form, is the result of the exponential equation which becomes the argument of the natural logarithm and the exponent in the exponential expression becomes the result of the natural logarithm equation, we can say that eA=BlnB=A{{e}^{A}}=B\Rightarrow \ln B=A.
We can now take log on both the left-hand side and the right-hand side to remove the exponent form and to write in logarithmic form, we get
loge3=log20.0855\Rightarrow \log {{e}^{3}}=\log 20.0855
We can now use the logarithmic identity, lne=1\ln e=1 in the above step, we get
3=log20.0855\Rightarrow 3=\log 20.0855
Therefore, the logarithmic form of the given exponential form e3=20.0855{{e}^{3}}=20.0855 is 3=log20.08553=\log 20.0855.

Note: We should always remember that a natural exponential equation in logarithmic form, is the result of the exponential equation which becomes the argument of the natural logarithm and the exponent in the exponential expression becomes the result of the natural logarithm equation, we can say that eA=BlnB=A{{e}^{A}}=B\Rightarrow \ln B=A. We should also know some logarithmic formula or identity such aslne=1\ln e=1.