Question
Question: How do you write an equation in slope intercept form given \(\left( { - 4,3} \right)\) and \(m = - 3...
How do you write an equation in slope intercept form given (−4,3) and m=−3?
Solution
In this question we have to find the equation of line in slope intercept form, where slope and a point is given, we know that slope intercept form is given by y=mx+b , where m is the slope of the line and b is the y-intercept of the line, now by substituting the given point in the slope intercept form we will get the y-intercept of the line, then by using y-intercept and the given slope we will get the required equation in slope intercept form.
Complete step by step solution:
Given point is (−4,3)and slope is m=−3,
We know that slope intercept form is given by y=mx+b , where m is the slope of the line and b is the y-intercept of the line,
As the given point passes through the equation, we can substitute the point in the slope intercept form, we get
So, here y=3, m=−3 and x=−4, by substituting the values in the slope intercept form we get,
⇒3=(−3)(−4)+b,
Now simplifying we get,
⇒3=12+b,
Now subtracting 12 on both sides we get,
⇒3−12=12+b−12,
Now simplifying we get,
⇒b=−9,
So, here we got y-intercept of the line b=−9 and slope of the line m=−3, now substituting the values in the slope intercept form i.e., y=mx+b we get,
⇒y=(−3)x−9,
Now simplifying we get
⇒y=−3x−9,
So, the slope intercept equation is y=−3x−9.
∴The required equation in slope intercept form will be equal to y=−3x−9.
Note: Remember that if the slope of a line is equal to zero then it is parallel to x-axis and if the slope tends to infinity then it is perpendicular to x-axis. Also, we can remember that if the x-coordinates of the two points through which the line passes are same it must be perpendicular to the x-axis and y-coordinates of the two points through which the line passes are same it must be parallel to the x-axis.