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Question: How do you write an equation in slope intercept form given \(\left( { - 4,3} \right)\) and \(m = - 3...

How do you write an equation in slope intercept form given (4,3)\left( { - 4,3} \right) and m=3m = - 3?

Explanation

Solution

In this question we have to find the equation of line in slope intercept form, where slope and a point is given, we know that slope intercept form is given by y=mx+by = mx + b , where mm is the slope of the line and bb is the yy-intercept of the line, now by substituting the given point in the slope intercept form we will get the yy-intercept of the line, then by using yy-intercept and the given slope we will get the required equation in slope intercept form.

Complete step by step solution:
Given point is (4,3)\left( { - 4,3} \right)and slope is m=3m = - 3,
We know that slope intercept form is given by y=mx+by = mx + b , where mm is the slope of the line and bb is the yy-intercept of the line,
As the given point passes through the equation, we can substitute the point in the slope intercept form, we get
So, here y=3y = 3, m=3m = - 3 and x=4x = - 4, by substituting the values in the slope intercept form we get,
3=(3)(4)+b\Rightarrow 3 = \left( { - 3} \right)\left( { - 4} \right) + b,
Now simplifying we get,
3=12+b\Rightarrow 3 = 12 + b,
Now subtracting 12 on both sides we get,
312=12+b12\Rightarrow 3 - 12 = 12 + b - 12,
Now simplifying we get,
b=9\Rightarrow b = - 9,
So, here we got yy-intercept of the line b=9b = - 9 and slope of the line m=3m = - 3, now substituting the values in the slope intercept form i.e., y=mx+by = mx + b we get,
y=(3)x9\Rightarrow y = \left( { - 3} \right)x - 9,
Now simplifying we get
y=3x9\Rightarrow y = - 3x - 9,
So, the slope intercept equation is y=3x9y = - 3x - 9.

\therefore The required equation in slope intercept form will be equal to y=3x9y = - 3x - 9.

Note: Remember that if the slope of a line is equal to zero then it is parallel to x-axis and if the slope tends to infinity then it is perpendicular to x-axis. Also, we can remember that if the x-coordinates of the two points through which the line passes are same it must be perpendicular to the x-axis and y-coordinates of the two points through which the line passes are same it must be parallel to the x-axis.