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Question: How do you write an equation given \(\left( { - 2,4} \right)\); \(m = 3\)?...

How do you write an equation given (2,4)\left( { - 2,4} \right); m=3m = 3?

Explanation

Solution

In this question, we have to find the equation of a line which has slope 33 and passes through the point (2,4)\left( { - 2,4} \right). It can be done by first finding the value of cc using the formula for the equation of a line. For this, substitute the value of m,x,ym,x,y into the equation. Next, move all terms not containing cc to the right side of the equation. Now that the values of mm (slope) and cc (y-intercept) are known, substitute them into y=mx+cy = mx + c to find the equation of the line. The equation obtained will be the required equation of the given line in slope intercept form.

Formula used:
The Slope Intercept Form of a Line:
The equation of a line with slope mm and making an intercept cc on yy-axis is y=mx+cy = mx + c.

Complete step by step solution:
We know that the slope intercept form of a line is the equation of a line with slope mm and making an intercept cc on yy-axis is y=mx+cy = mx + c.
Given: (2,4)\left( { - 2,4} \right); m=3m = 3
So, we have to write an equation in the form of y=mx+cy = mx + c, the equation of a line with slope mm and making an intercept cc on yy-axis.
First, find the value of cc using the formula for the equation of a line.
Now, use the formula for the equation of a line to find cc.
y=mx+cy = mx + c
Substitute the value of mm into the equation, we get
y=3x+c\Rightarrow y = 3x + c
Substitute the value of xx into the equation, we get
y=3(2)+c\Rightarrow y = 3\left( { - 2} \right) + c
Substitute the value of yy into the equation, we get
4=3(2)+c\Rightarrow 4 = 3\left( { - 2} \right) + c
Next, find the value of cc.
For this, rewrite the equation as 3(2)+c=43\left( { - 2} \right) + c = 4.
3(2)+c=4\Rightarrow 3\left( { - 2} \right) + c = 4
Multiply 33 by 2 - 2, we get
6+c=4\Rightarrow - 6 + c = 4
Now, move all terms not containing cc to the right side of the equation.
Add 66 to both sides of the equation.
c=4+6\Rightarrow c = 4 + 6
Add 44 and 66.
c=10\therefore c = 10
Now that the values of mm (slope) and cc (y-intercept) are known, substitute them into y=mx+cy = mx + c to find the equation of the line.
y=3x+10\Rightarrow y = 3x + 10

Final solution: Hence, the equation of the line is y=3x+10y = 3x + 10.

Note: We can directly find the equation of line by substituting x1=2{x_1} = - 2, y1=4{y_1} = 4 and m=3m = 3 in equation of the line yy1=m(xx1)y - {y_1} = m\left( {x - {x_1}} \right).
y4=3(x+2)\Rightarrow y - 4 = 3\left( {x + 2} \right)
Now, apply distributive property in the above equation, i.e., multiplying each addend individually by the number and then adding the products together.
y4=3x+6\Rightarrow y - 4 = 3x + 6
Now we have to isolate the variable term, yy on one side by performing the same mathematical operations on both sides of the equation.
So, adding 44 to both sides of the equation, we get
y4+4=3x+6+4\Rightarrow y - 4 + 4 = 3x + 6 + 4
It can be written as
y=3x+10\Rightarrow y = 3x + 10
Final solution: Hence, the equation of the line is y=3x+10y = 3x + 10.