Question
Question: How do you verify \[\tan \left( \theta +\dfrac{\pi }{2} \right)=-\cot \theta \]?...
How do you verify tan(θ+2π)=−cotθ?
Solution
To prove a statement, we must show that either the left-hand side or right-hand side can be expressed as the other side. To prove this statement, we must know the trigonometric expansion formula of tan(A+B). tan(A+B)is expanded as 1−tanAtanBtanA+tanB. We will use this expansion formula to solve this question.
Complete step-by-step answer:
We are asked to prove the statement tan(θ+2π)=−cotθ. The LHS of the above statement is tan(θ+2π), and the right-hand side of the statement is −cotθ. Let’s take the left-hand side of the expression. We can use the expansion formula of tan(A+B), here we have A=θ&B=2π.
We know the expansion formula for tan(A+B) is 1−tanAtanBtanA+tanB, substituting the values of A, and B. we get
⇒1−tanθtan2πtanθ+tan2π
Dividing the numerator and denominator by tan2π, we get
⇒tan2π1−tanθtan2πtan2πtanθ+tan2π=tan2π1−tanθtan2πtanθ+1
We know that tana1=cota, using this in the above expression, it can be written as
⇒cot2π−tanθtanθcot2π+1
We know cot2π=0, substituting its value in the above expression, we get
⇒0−tanθ0+1=−tanθ1
Again, using the property tana1=cota, the above expression can be written as
⇒−cotθ
Hence, as the left-hand side of the given statement can be expressed as the right-hand side. This statement is proved.
Note: The given statement is one of the important trigonometric properties, and so it should be remembered. As it will be useful in solving other trigonometric questions including evaluation of expression or proofs. We can also prove the properties sin(θ+2π)=cosθ, and cosec(θ+2π)=secθ by a similar method.