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Question

Question: How do you use the change of base formula and a calculator to evaluate the logarithm \( {\log _8}77?...

How do you use the change of base formula and a calculator to evaluate the logarithm log877?{\log _8}77?

Explanation

Solution

Hint : As we know that the logarithm is the inverse function to exponentiation. That means the logarithm of a given number xx is the exponent to which another fixed number, the base b, must be raised , to produce that number xx . As per the definition of a logarithm logab=c{\log _a}b = c which gives that ac=b{a^c} = b . Here in the above expression the base is 88 . And we also have to assume that if no base bb is written then the base is always 10. This is an example of base ten logarithm because 1010 is the number that is raised to a power.

Complete step-by-step answer :
As per the given question we have log877.{\log _8}77. .
We can use a formula that allows us to rewrite a logarithm in terms of logs written with another base. The change of base formula is given as
logba=logcalogcb{\log _b}a = \dfrac{{{{\log }_c}a}}{{{{\log }_c}b}} , in which value of a=8a = 8 and b=77b = 77 .
So by applying the formula we have log877=log77log8{\log _8}77 = \dfrac{{\log 77}}{{\log 8}} .
It can be written as ln77ln8\dfrac{{\ln 77}}{{\ln 8}} , so it gives us log877=4.343812.079442=2.08893{\log _8}77 = \dfrac{{4.34381}}{{2.079442}} = 2.08893
Hence the value of log877{\log _8}77 is 2.08892.0889 (approx.).

Note : We should always be careful while solving logarithm formulas and before solving this kind of problems we should know all the rules of logarithm and exponentiation. We have to keep in mind that when a logarithm is written without any base, like this: log100\log 100 then this usually means that the base is already there which is 1010 . It is called a common logarithm or decadic logarithm, is the logarithm to the base 1010 . One way we can approach log problems is to keep in mind that ab=c{a^b} = c and logac=b{\log _a}c = b .