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Question: How do you use the Change of Base Formula and a calculator to evaluate the logarithms \( {\log _2}1 ...

How do you use the Change of Base Formula and a calculator to evaluate the logarithms log21{\log _2}1 ??

Explanation

Solution

Hint : Given a logarithm of the form logbM{\log _b}M , use the change-of-base formula to rewrite it as a quotient of logs with any positive base nn , where n1n \ne 1 . determine the new base nn , remembering that the common log\log , log(x)\log \left( x \right) , has base 10 and the natural log\log , ln(x)\ln (x) , has base ee . Rewrite the log\log as a quotient using the change-of-base formula:

Complete step-by-step answer :
The change-of-base formula can be used to evaluate a logarithm with any base.
Given a logarithm in the question of the form logbM{\log _b}M , by use the change of base formula the given logarithm function can be rewrite as a quotient of logs with any positive real numbers M, b, and n, where n1n \ne 1 and b1b \ne 1 , as follows
The numerator of the quotient will be a logarithm with base n and argument M and the denominator of the quotient will be a logarithm with base n and argument b.
By this, the change-of-base formula can be used to rewrite a logarithm with base n as the quotient of common or natural logs.
logbM=lnMlnb{\log _b}M = \dfrac{{\ln M}}{{\ln b}} and logbM=lognMlognb{\log _b}M = \dfrac{{{{\log }_n}M}}{{{{\log }_n}b}}
Remember the standard base value n for common log\log , log(x)\log \left( x \right) has base value 10 and the natural log\log , ln(x)\ln (x) has base ee .
Now to evaluate the given common logarithms log21{\log _2}1 by use the change of base formula is
For common logarithm as we know the value of new base n is 10.
log21=log101log102\Rightarrow \,\,{\log _2}1 = \dfrac{{{{\log }_{10}}1}}{{{{\log }_{10}}2}}
By using a logarithm calculator with base 10 the value of log101=0{\log _{10}}1 = 0 and log102=0.301029996{\log _{10}}2 = 0.301029996 .
log21=00.301029996\Rightarrow \,\,{\log _2}1 = \dfrac{0}{{0.301029996}}
log21=0\therefore \,\,\,\,{\log _2}1 = 0
Therefore, by using the Change of Base Formula and a calculator the value of logarithms log21{\log _2}1 is 00 .
So, the correct answer is “0”.

Note : The logarithmic function is a reciprocal or the inverse of exponential function. To solve the question, we must know about the properties of the logarithmic function. There are properties on addition, subtraction, product, division etc., on the logarithmic functions. We have to change the base of the log function and to simplify the given question.