Question
Question: How do you use the binomial series to expand \[\dfrac{1}{{{\left( 2+x \right)}^{3}}}\]?...
How do you use the binomial series to expand (2+x)31?
Solution
In this problem, we have to use the binomial series to expand the given expression. We know that the binomial series is a kind of formula that helps us to expand binomials raised to the power of any number using the binomial theorem. The binomial series formula is (a+b)n=an+nan−1b+1×2n(n−1)an−2b2+1×2×3n(n−1)(n−2)an−3b3.... We can write the given expression in terms of the right-hand side of the binomial theorem and we can substitute the values, a, b. n in the binomial series formula to expand it.
Complete step by step answer:
We have to use the binomial theorem to expand (2+x)31.
We know that the binomial series is a kind of formula that helps us to expand binomials raised to the power of any number using the binomial theorem.
We know that the binomial series is,
(a+b)n=an+nan−1b+1×2n(n−1)an−2b2+1×2×3n(n−1)(n−2)an−3b3...
We can write the given expression as,
⇒(2+x)−31=(2+x)−3
Here, a = 2, b = x, n = -3.
We can now expand the expression using binomial series, we get
⇒(2+x)−3=2−3+(−3)(2−4)x+1×2−3(−4)2−5x2+6−3(−4)(−5)2−6x3...
We can now simplify the above step, we get
⇒(2+x)31=81−163x+163x2−325x3+...
Therefore, the expansion using binomial series is, (2+x)31=81−163x+163x2−325x3+....
Note: we should know that, any number with the negative power, can be written in a fraction form, by writing it in the denominator with the same power as positive. We should remember that the binomial series is a kind of formula that helps us to expand binomials raised to the power of any number using the binomial theorem.