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Question: How do you use the binomial probability formula to find the probability of x successes given probabi...

How do you use the binomial probability formula to find the probability of x successes given probability p of success on a single trial for n=6, x=4, p=0.75?

Explanation

Solution

In the binomial probability, the number of successes X in ‘n’ trials of a binomial experiment is called a binomial random variable. The probability distribution of the random variable X is called a binomial distribution, and is given by the formula as below:
P(X)=CxnpxqnxP\left( X \right) = C_x^np^xq^{{n - x}}
Where n is the number of trials, x is 0, 1, 2..., n, p is the probability of success in a single trial, q is the probability of failure in a single trial and the value of q is 1-p. P(X) gives the probability of successes in n binomial trials.
The combination formula is Cxn=n!x!(nx)!C_x^n = \dfrac{{n!}}{{x!\left( {n - x} \right)!}}.

Complete step-by-step answer:
We already know the binomial probability formula
P(X)=CxnpxqnxP\left( X \right) = C_x^np^xq^{{n - x}}
The value of q is 1-p.
P(X)=Cxnpxqnx\Rightarrow P\left( X \right) = C_x^np^xq^{{n - x}}
Let us substitute the values n=6, x=4, and p=0.75.
P(X)=C46(0.75)4(10.75)64\Rightarrow P\left( X \right) = C_4^6{\left( {0.75} \right)^4}{(1 - 0.75)^{6 - 4}} ...(1)
The combination formula is
Cxn=n!x!(nx)!C_x^n = \dfrac{{n!}}{{x!\left( {n - x} \right)!}}
Let us substitute the value of n and x.
C46=6!4!(64)!\Rightarrow C_4^6 = \dfrac{{6!}}{{4!\left( {6 - 4} \right)!}}
Therefore,
C46=6!4!×2!\Rightarrow C_4^6 = \dfrac{{6!}}{{4! \times 2!}}
So,
C46=6×5×4×3×2×14×3×2×1×2×1\Rightarrow C_4^6 = \dfrac{{6 \times 5 \times 4 \times 3 \times 2 \times 1}}{{4 \times 3 \times 2 \times 1 \times 2 \times 1}}
Let us simplify it.
C46=15\Rightarrow C_4^6 = 15
Now, substitute the value of combination in equation (1).
P(X)=15(0.75)4(10.75)64\Rightarrow P\left( X \right) = 15{\left( {0.75} \right)^4}{(1 - 0.75)^{6 - 4}}
P(X)=15(0.75)4(0.25)2\Rightarrow P\left( X \right) = 15{\left( {0.75} \right)^4}{(0.25)^2}
So, the answer will be
P(X)=0.297\Rightarrow P\left( X \right) = 0.297

Hence, the probability of success is 0.297.

Note:
A binomial probability is one that possesses the following properties:
The experiment consists of n repeated trials.
Each trial results in an outcome that may be classified as a success or a failure. Based on these two conditions the name is called binomial.
The probability of success remains constant from trial to trial and repeated trials are independent.