Solveeit Logo

Question

Question: How do you tell whether \[1,2,4,7,11\] is in arithmetic progression?...

How do you tell whether 1,2,4,7,111,2,4,7,11 is in arithmetic progression?

Explanation

Solution

In this question, we have to find whether the given sequence is an arithmetic progression. This can be done by finding the common difference, we will use the common difference formula which is given by, Common difference (d)(d) =an+1an = {a_{n + 1}} - {a_n}. So, if all the common differences are equal then we can say that they are in arithmetic progression.

Complete step by step solution:
An arithmetic progression is a sequence where the difference between every two consecutive terms is the same. An arithmetic progression is a sequence where each term, except the first term, is obtained by adding a fixed number to its previous term.
The general arithmetic progression is of the form a,a+d,a+2d,...a,a + d,a + 2d,... where aa is the first term and dd is the common difference. The nth{n^{th}} term of the arithmetic progression is defined as an=a0+(n1)d{a_n} = {a_0} + \left( {n - 1} \right)d.
Now the given sequence is 1,2,4,7,111,2,4,7,11. Here, a1=1, a2=2, a3=4, a4=7 and a5=11{a_1} = 1,{\text{ }}{a_2} = 2,{\text{ }}{a_3} = 4,{\text{ }}{a_4} = 7{\text{ and }}{a_5} = 11.
The difference between a1{a_1} and a2{a_2} is given by a2a1=21{a_2} - {a_1} = 2 - 1 i.e., a2a1=1{a_2} - {a_1} = 1.
The difference between a2{a_2} and a3{a_3} is given by a3a2=42{a_3} - {a_2} = 4 - 2 i.e., a3a2=2{a_3} - {a_2} = 2.
The difference between a3{a_3} and a4{a_4} is given by a4a3=74{a_4} - {a_3} = 7 - 4 i.e., a4a3=3{a_4} - {a_3} = 3.
The difference between a4{a_4} and a5{a_5} is given by a5a4=117{a_5} - {a_4} = 11 - 7 i.e., a5a4=4{a_5} - {a_4} = 4.
Here, we can see that the difference between a term and its immediately preceding term is not the same.
Therefore, 1,2,4,7,111,2,4,7,11 is not arithmetic.

Note:
1,2,4,7,111,2,4,7,11 is also not a geometric sequence. Geometric sequence is a sequence of non-zero numbers where each term after the first is found by multiplying the previous one by a fixed, non-zero number called the common ratio. But here 21=2\dfrac{2}{1} = 2, 42=2\dfrac{4}{2} = 2 but 742\dfrac{7}{4} \ne 2. Common ratio of all the terms is not equal. Therefore, it is also not a geometric sequence.