Question
Question: How do you solve using the completing the square method \( {x^2} - 30x = - 125 \) ?...
How do you solve using the completing the square method x2−30x=−125 ?
Solution
According to the question we have to solve the given quadratic expression x2−30x=−125 which is as mentioned in the question with the help of completing the square. So, to obtain the roots/zeros of the given quadratic expression with the help of the completing square method first of all we have to divide the whole quadratic expression with the coefficient of x2 but according to the given expression the coefficient of x2 is 1 so on dividing the whole expression with 1 there will be no change in the equation.
Now, to obtain the given quadratic expression in the form of a complete square we have to divide the coefficient of x with 2 and then we have to add and subtract the square of that in the both sides of the expression.
Now, we have to right the left hand side as a perfect square and simply the right hand side.
Now, we have to take the square root in the both hand side of the given expression.
Complete step by step answer:
Step 1: First of all we have to divide the whole quadratic expression with the coefficient of x2 but according to the given expression the coefficient of x2 is 1 so on dividing the whole expression with 1 there will be no change in the equation.
Step 2: Now, to obtain the given quadratic expression in the form of complete square we have to divide the coefficient of x with 2 and then we have to add and subtract the square of that in the both sides of the expression. Hence,
⇒x2−30x+(−230)2=−125+(−230)2
On solving the expression as obtained just above,
⇒x2−30x+4900=−125+4900 ⇒x2−30x+4900=4−500+900 ⇒x2−30x+4900=100
Step 3: Now, we have to right the left hand side as a perfect square and simply right hand side. Hence,
⇒(x−15)2=100
Step 4: Now, we have to take the square root in the both hand side of the given expression. Hence,
⇒(x−15)=100 ⇒(x−15)=±10
Step 5: Now, we just have to solve the expression as obtained in the solution step 4 by adding and subtracting the term of the expression. Hence,
⇒x−15=10 ⇒x=10+15 ⇒x=25
And,
⇒x−15=−10 ⇒x=−10+15 ⇒x=5
Hence, we have determined the solution or the roots/zeros of the given quadratic expression which are x=5,25 .
Note: It is necessary that we have to divide the whole expression by dividing the coefficient of x2 so that we can easily determine the complete square of the given quadratic expression.
It is necessary that we have to take the coefficient of x then we have to half the obtained coefficient, then we have to square it and add it to the both sides of the expression.