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Question

Question: How do you solve the system of equations \(3x + y = 23\) and \(4x - y = 19\)?...

How do you solve the system of equations 3x+y=233x + y = 23 and 4xy=194x - y = 19?

Explanation

Solution

It is given as we have to solve the given system of simultaneous equations by the elimination method. So, add both equations. After addition, you will find that y is eliminated and you will be left with x and then simplify and get the value of x and then substitute this value of x in any of the equations. It will give you the value of x.

Complete step-by-step answer:
The two simultaneous equations given in the question are:
3x+y=23\Rightarrow 3x + y = 23 ….. (1)
4xy=19\Rightarrow 4x - y = 19 ….. (2)
We are going to solve the above simultaneous equations by elimination method in which we add both the equations and then y will be eliminated and we get the value of x.
Now, add both equations,
3x+y=23 4xy=19 7x=42\begin{array}{l} 3x + y = 23\\\ \underline {4x - y = 19} \\\ 7x\,\,\,\,\,\,\,\,\, = 42 \end{array}
Now, divide, both sides by 7,
x=6\Rightarrow x = 6
Plugging this value of x in equation (1) we get,
3×6+y=23\Rightarrow 3 \times 6 + y = 23
Multiply the terms,
18+y=23\Rightarrow 18 + y = 23
Subtract 18 from both sides,
18+y18=2318\Rightarrow 18 + y - 18 = 23 - 18
Simplify the terms,
y=5\Rightarrow y = 5

Hence, the value of x is 6 and y is 5.

Note:
This question can be done in another way also.
The two simultaneous equations given in the question are:
3x+y=23\Rightarrow 3x + y = 23 ….. (1)
4xy=19\Rightarrow 4x - y = 19 ….. (2)
We are going to solve the above simultaneous equations by substitution method in which find the value of y in terms of x from equation (2) and then substitute it in equation (2) to find the value of x.
The value of y in terms of x in equation (2)
4xy=19\Rightarrow 4x - y = 19
Simplify the terms,
y=4x19\Rightarrow y = 4x - 19 ….. (3)
Substitute the value in equation (1),
3x+(4x19)=23\Rightarrow 3x + \left( {4x - 19} \right) = 23
Simplify the terms,
3x+4x=23+19\Rightarrow 3x + 4x = 23 + 19
Add the like terms,
7x=42\Rightarrow 7x = 42
Now, divide, both sides by 7,
x=6\Rightarrow x = 6
Plugging this value of x in equation (3) we get,
y=4×619\Rightarrow y = 4 \times 6 - 19
Multiply the terms,
y=2419\Rightarrow y = 24 - 19
Subtract the terms,
y=5\Rightarrow y = 5
Hence, the value of x is 6 and y is 5.