Question
Question: How do you solve the system of equations \(3x + y = 23\) and \(4x - y = 19\)?...
How do you solve the system of equations 3x+y=23 and 4x−y=19?
Solution
It is given as we have to solve the given system of simultaneous equations by the elimination method. So, add both equations. After addition, you will find that y is eliminated and you will be left with x and then simplify and get the value of x and then substitute this value of x in any of the equations. It will give you the value of x.
Complete step-by-step answer:
The two simultaneous equations given in the question are:
⇒3x+y=23 ….. (1)
⇒4x−y=19 ….. (2)
We are going to solve the above simultaneous equations by elimination method in which we add both the equations and then y will be eliminated and we get the value of x.
Now, add both equations,
3x+y=23 4x−y=19 7x=42
Now, divide, both sides by 7,
⇒x=6
Plugging this value of x in equation (1) we get,
⇒3×6+y=23
Multiply the terms,
⇒18+y=23
Subtract 18 from both sides,
⇒18+y−18=23−18
Simplify the terms,
⇒y=5
Hence, the value of x is 6 and y is 5.
Note:
This question can be done in another way also.
The two simultaneous equations given in the question are:
⇒3x+y=23 ….. (1)
⇒4x−y=19 ….. (2)
We are going to solve the above simultaneous equations by substitution method in which find the value of y in terms of x from equation (2) and then substitute it in equation (2) to find the value of x.
The value of y in terms of x in equation (2)
⇒4x−y=19
Simplify the terms,
⇒y=4x−19 ….. (3)
Substitute the value in equation (1),
⇒3x+(4x−19)=23
Simplify the terms,
⇒3x+4x=23+19
Add the like terms,
⇒7x=42
Now, divide, both sides by 7,
⇒x=6
Plugging this value of x in equation (3) we get,
⇒y=4×6−19
Multiply the terms,
⇒y=24−19
Subtract the terms,
⇒y=5
Hence, the value of x is 6 and y is 5.