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Question: How do you solve the system of equations \(3x - 2y = 7\) and \(x + 3y = - 5\)?...

How do you solve the system of equations 3x2y=73x - 2y = 7 and x+3y=5x + 3y = - 5?

Explanation

Solution

Where we are given a pair of linear equations and we have to find the value of x and y by using the given equation. We can solve the equation by the method of elimination or by using the method of substitution for the method of substitution. First we will find the value of one variable in the form of another for example we will find the value of x in terms of y then substitute that value in another equation. Then we will solve the equation and find the value of that variable. After that substitute the value of that variable in another equation and find the value of the remaining one variable.

Complete step-by-step answer:
Step1: We are given a pair of linear equations 3x2y=73x - 2y = 7 and x+3y=5x + 3y = - 5 by applying the method of substitution we will find the value of both variables. We will solve the second equation for xx:
x+3y=5\Rightarrow x + 3y = - 5
Subtracting 3y3y from both sides:
x+3y3y=53y\Rightarrow x + 3y - 3y = - 5 - 3y
On proper rearrangement we will get:
x=53y\Rightarrow x = - 5 - 3y
Step2: Now we will substitute the value of x in the first equation and solve for yy:
3(53y)2y=7\Rightarrow 3( - 5 - 3y) - 2y = 7
159y2y=7\Rightarrow - 15 - 9y - 2y = 7
Adding 1515 both the sides we will get:
151511y=15+7\Rightarrow 15 - 15 - 11y = 15 + 7
011y=22\Rightarrow 0 - 11y = 22
Dividing both sides by11 - 11:
11y11=2211\Rightarrow \dfrac{{ - 11y}}{{ - 11}} = \dfrac{{22}}{{ - 11}}
y=2\Rightarrow y = - 2
Step3: Substitute 2 - 2 for y in the solution to the second equation at the end of step1 and calculate xx:
x=5(3×2)\Rightarrow x = - 5 - \left( {3 \times - 2} \right)
On further solving we will get:
x=5+6\Rightarrow x = - 5 + 6
x=1x = 1
So the solution is x=1;y=2x = 1;y = - 2

Hence the solution is x=1;y=2x = 1;y = - 2

Note:
This type of question we can solve by two methods: first is substitution and the second one is elimination. In this method the main thing is to find the value of one variable in terms of other students mainly doing the mistakes here.
Alternate method:
We are given two equations i.e.
3x2y=73x - 2y = 7…(1)
x+3y=5x + 3y = - 5….(2)
Multiply (2) equation by 33
3x+9y=153x + 9y = - 15…(3)
Subtract equation (3) from (1)
3x+9y=153x+ 9y = - 15
()3x2y=7\underline {( - ){{3x}} - 2y = 7}
11y=2211y = - 22
Now dividing the both sides by 1111
y=2y = - 2
Substitute y=2y = - 2 in equation (1) we get the value of x
3x+4=7\Rightarrow 3x + 4 = 7
3x=3\Rightarrow 3x = 3
x=1\Rightarrow x = 1
Here also we will get the same solution i.e. x=1;y=2x = 1;y = - 2