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Question: How do you solve the system by graphing \(2x-y=4\) and \(4x-2y=-8?\)...

How do you solve the system by graphing 2xy=42x-y=4 and 4x2y=8?4x-2y=-8?

Explanation

Solution

As we know that the above equation has to be solved graphically we can be plotted on a coordinate plane.So we have to find the slope and interception on the planes.

Complete step by step solution: As we want to solve the above equation in graphing form i.e. 2xy=82x-y=-8
So,
Now we want to convert 2xy=42x-y=4
Thus slope intercept we get
y=2x4y=2x-4
i.e. 22 is the given slope and now intercepting it an yy-axis.
i.e. 4.-4.
So now further solving the equation 4x2y=84x-2y=-8 into slope, we get
2y=4x+82y=4x+8 or y=2x+4y=2x+4
So, the slope is 22
And now on yy-axis is 44
Thus we are seeing the above equation we get, that the line are parallel.
Hence, we will get no solution.
Graph \left\\{ \left( 2x-y-4 \right)\left( 4x-2y+8 \right)=0\left[ -10,10,-5,5 \right] \right\\}

Additional Information:
We can also solve such questions by other ways,
Like here, we can use either substitution method or any alternate method.
As, we have,
2xy=42x - y = 4 and 4x2y=84x - 2y = - 8
Here, the value of the coefficient of x In first equation is 2 and the value of the coefficient of x in the second equation is 4.
So, for solving the question,
We can make the value of coefficient of x in both the equations,
For that,
We need to multiply the first equation by 4 and the second equation by 2.
Then after subtracting the formed equations we can determine the value of x and y.
As we had solved the equation above, we can further solve it.
Example: 2x=42x=4 and y=3y=-3
Now we are taking lines passing through x=42=2x=\dfrac{4}{2}=2
Further the next equation i.e. horizontal line. y=3y=-3
Above two point intersect at PP i.e. (2,3)\left( 2,-3 \right)

Note:
We can also have example
x2y=2x-2y=-2 and x2y=3x-2y=3
Now taking the first equation
x2y=2x-2y=-2
Now establishing the equation of xx and yywith zero (0,1)\left( 0,1 \right) and (2,0)\left( -2,0 \right)
Now further solving the second equation
x2y=3x-2y=3
(0,112)\left( 0,-1\dfrac{1}{2} \right) and (3,0)\left( 3,0 \right)