Question
Question: How do you solve the system \[2x+y-z=2\], \[-x-3y+z=-1\] and \[-4x+3y+z=-4\]?...
How do you solve the system 2x+y−z=2, −x−3y+z=−1 and −4x+3y+z=−4?
Solution
In this problem, we have to solve the given system of equations to find the value of x, y and z. We can first take the equation (1) and (2) for subtraction to get the equation (4), then we can take the equation (2) and (3) for subtraction to get the new equation (6), we can the solve the equation (4) and (6), to get any one of the values of x, y, z. We can substitute the resulting values in any of the equations to get another value. We can repeat this method until finding all the three values.
Complete step by step solution:
We know that the given system of equations to be solved are,
2x+y−z=2 ……… (1)
−x−3y+z=−1 …….. (2)
−4x+3y+z=−4……. (3)
We can now subtract the equation by elimination method.
We should know that to solve by elimination method, we should have similar terms to be cancelled, so we can multiply both equations with numbers to get similar terms.
We can now add the equation (1) and (2), we get