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Question

Question: How do you solve the quadratic equation \({{x}^{2}}+11x=7\)?...

How do you solve the quadratic equation x2+11x=7{{x}^{2}}+11x=7?

Explanation

Solution

In this problem we need to solve the given quadratic equation i.e., we need to calculate the values of xx where the given equation is satisfied. For solving a quadratic equation, we have several methods. But in the problem, we are going to use the quadratic formula which is given by x=b±b24ac2ax=\dfrac{-b\pm \sqrt{{{b}^{2}}-4ac}}{2a}.To use the above formula we need to have the quadratic equation in standard form which is ax2+bx+c=0a{{x}^{2}}+bx+c=0, so we will simplify the given equation and convert it into the standard form. After that we will compare the given equation with the standard quadratic equation ax2+bx+c=0a{{x}^{2}}+bx+c=0 and write the values of aa, bb, cc. Now we will substitute those values in the formula x=b±b24ac2ax=\dfrac{-b\pm \sqrt{{{b}^{2}}-4ac}}{2a} and simplify the obtained equation to get the required result.

Complete step by step solution:
Given equation x2+11x=7{{x}^{2}}+11x=7.
Shifting the constant which is right hand side to left hand side, then we will get
x2+11x7=0\Rightarrow {{x}^{2}}+11x-7=0
Comparing the above quadratic equation with standard quadratic equation ax2+bx+c=0a{{x}^{2}}+bx+c=0, then we will get the values of aa, bb, cc as
a=1a=1, b=11b=11, c=7c=-7.
We have the quadratic formula for the solution as
x=b±b24ac2ax=\dfrac{-b\pm \sqrt{{{b}^{2}}-4ac}}{2a}
Substituting the values of aa, bb, cc in the above equation, then we will get
x=(11)±(11)24(1)(7)2(1)\Rightarrow x=\dfrac{-\left( 11 \right)\pm \sqrt{{{\left( 11 \right)}^{2}}-4\left( 1 \right)\left( -7 \right)}}{2\left( 1 \right)}
We know that when we multiplied a negative sign with a positive sign, then we will get a negative sign. Applying the above rule and simplifying the above equation, then we will get
x=11±121+282 x=11±1492 \begin{aligned} & \Rightarrow x=\dfrac{-11\pm \sqrt{121+28}}{2} \\\ & \Rightarrow x=\dfrac{-11\pm \sqrt{149}}{2} \\\ \end{aligned}
In the above equation we have the value 149\sqrt{149}. We can observe that the number 149149 is a prime number, so we can’t simplify the value of 149\sqrt{149}.
Hence the solution of the given quadratic equation x2+11x=7{{x}^{2}}+11x=7 is 11±1492\dfrac{-11\pm \sqrt{149}}{2}.

Note: There are several methods to solve the quadratic equation. But the easiest one is the using quadratic formula. There are less chances of making mistakes in this method. So, when they don’t mention the method to use, we can freely use this method and solve the equation.