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Question

Question: How do you solve the equation \(-{{x}^{2}}-7x=0\) by graphing?...

How do you solve the equation x27x=0-{{x}^{2}}-7x=0 by graphing?

Explanation

Solution

In this question we have been with a polynomial equation which we have to solve by graphing. Graphing is a method by which the expression is expressed in the form of a two-dimensional graph and then the solutions are derived from it. We will use a graphing tool to first draw the graph of the equation and then solve for the values of the function at 00 and get the required solutions.

Complete step by step solution:
We have the expression given to us as:
x27x=0\Rightarrow -{{x}^{2}}-7x=0
Now since we have to find the solution of the function at the value 00, we can write the expression in terms of a function of xx as:
f(x)=x27x\Rightarrow f\left( x \right)=-{{x}^{2}}-7x.
Now on using a graphing tool, we get the graph of the function as:

Now from the graph, we can see that the value of the function crosses f(x)=0f\left( x \right)=0 at two points which are 00 and 7-7 therefore, on considering the points as AA and BB, we get the graph as:

Therefore, through graphing A=0A=0 and B=7B=-7 are the two solutions to the expression.

Note: In this question we have used the method of graphing. This problem can also be solved by taking out the common values and equating them with 00.
Consider the expression as:
x27x=0\Rightarrow -{{x}^{2}}-7x=0
Now we can see that xx is common in both the terms therefore on taking it out as common, we get:
x(x+7)=0\Rightarrow -x\left( x+7 \right)=0
Now we know that when ab=0ab=0 either a=0a=0 or b=0b=0 therefore, we get:
x=0-x=0 and x+7=0x+7=0
On rearranging, we get:
x=0x=0 and x=7x=-7 as the two required solutions for the expression.