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Question

Question: How do you solve \[\tan x = 0\] \[?\]...

How do you solve tanx=0\tan x = 0 ??

Explanation

Solution

We need to know the trigonometric table values and the basic definition tanθ\tan \theta .

To solve the given problem we need to find the values of θ\theta . Also, we need to know the process of calculating the value of tanθ\tan \theta the scientific calculator. We need to know the degree value π\pi . Also, we need to know the relation between sinθ,cosθ,\sin \theta ,\cos \theta , and tanθ\tan\theta .

Complete step by step solution:
The given question is shown below,
tanx=0\tan x = 0
We need to find the value θ\theta from the above equation. Before that, we need to know the basic definition of tanθ\tan \theta .
The above figure represents a triangle marked with the opposite side, adjacent side, and hypotenuse side according to the position of θ\theta .
The above figure is used to represent the definition of sinθ,cosθ,\sin \theta ,\cos \theta , and tanθ\tan \theta . Let’s see the definitions of sinθ,cosθ,\sin \theta ,\cos\theta , and tanθ\tan \theta ,
sinθ=oppositehypotenuse\sin \theta = \dfrac{{opposite}}{{hypotenuse}}
cosθ=adjacanthypotenuse\cos \theta = \dfrac{{adjacant}}{{hypotenuse}}
tanθ=oppositeadjacant\tan \theta = \dfrac{{opposite}}{{adjacant}}
From the above three equations, we can define the tanθ\tan \theta as follows,
tanθ=sinθcosθ\tan \theta = \dfrac{{\sin \theta }}{{\cos \theta }} (A) \to \left( A \right)
We need to find the value of tanx=0\tan x = 0 . So, we get
x=arctan(0)x = \arctan \left( 0 \right)
We know that,
sin(0)=0\sin \left( 0 \right) = 0
0=arcsin(0)0 = \arcsin \left( 0 \right)

\sin \left( \pi \right) = 0 \\\ \pi = \arcsin \left( 0 \right) \\\\$$ From the equation, $$\left( A \right)$$ we get when the value of $$\sin \theta $$ is $$0$$ , then automatically the value of $$\tan \theta $$ is $$0$$ $$(i.e\tan x = 0)$$ . So, we get

\tan \left( 0 \right) = 0 \\
0 = \arctan \left( 0 \right) \\
\tan \left( \pi \right) = 0 \\
\pi = \arctan \left( 0 \right) \\

So when $$\theta $$ the value is $$0,\pi ,2\pi ,3\pi ,......$$ the value of $$\tan \theta $$ becomes $$0$$ . **So, the final answer is, If $$\tan x = 0$$ , then the value of $$x = 0,\pi ,2\pi ,3\pi ,....$$ ** **Note:** In this type of question we would find the value of $$x$$ from the given equation. In this problem, we use trigonometric table values for finding the value of $$x$$ . Also, we can use a scientific calculator to find the value $$x$$ . On finding the $$x$$ value in the scientific calculator we can use radian mode or degree mode. If we want to find $$x$$ value in decimal we can use radian mode otherwise we can use degree mode.