Question
Question: How do you solve \(\sin \left( {2x} \right) = \dfrac{1}{2}\) ?...
How do you solve sin(2x)=21 ?
Solution
The question belongs to the solution of trigonometric equations. In this question we will convert the right hand side of the equation in trigonometric ratio. For this we will take sin to the right hand side of the equation by keeping in mind that the original trigonometric equation should not be changed. We will find the angle from the standard trigonometric angle ratio table so that sin of the respective angle gives the appropriate value as required. Then we will solve the equation for the value of the trigonometric ratio.
Complete step by step solution:
Step: 1 the given trigonometric equation is,
sin(2x)=21
Take sin to the right hand side of the equation.
⇒sin2x=sin30
We know that the value of sin30=21 .
Step: 2 now compare the both side of the equation to find the value of x .
⇒2x=30
Solve the linear equation to find the value of x.
Divide both side of the equation by two to find the value of x .
⇒2x=30 ⇒22x=230 ⇒x=15
Step: 3 now consider the other angle at which sin gives the value as required.
We know that the value of sin150=21.
Now again take sin of both side of the equation.
⇒sin2x=sin150
Compare the both side of the equation to solve the given trigonometric equation.
⇒2x=150
Solve the linear equation to find the value of x .
⇒2x=150 ⇒x=2150 ⇒x=75
Final Answer:
Therefore the solution of the given equation is x=15 and x=75 .
Note:
You are advised to remember the table of standard trigonometric ratios of angle. They must know to solve the linear equation. They should solve the given equation by taking sin to both sides of the equation.