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Question

Question: How do you solve \(\sin 2x-\cos x=0\)?...

How do you solve sin2xcosx=0\sin 2x-\cos x=0?

Explanation

Solution

We will use the double angle formula for the sine function, which is given as sin2x=2sinxcosx\sin 2x=2\sin x\cos x. Then we will take the cosine function common. After that we will get two factors of the given equation such that their product is zero. Then we will equate these factors to zero and find the possible values of the variable xx.

Complete step by step answer:
The given equation is sin2xcosx=0\sin 2x-\cos x=0. We know that there is a double angle formula for the sine function. This formula is given as sin2x=2sinxcosx\sin 2x=2\sin x\cos x. Substituting this formula in the given equation, we get the following expression,
2sinxcosxcosx=02\sin x\cos x-\cos x=0
Both the terms on the left hand side have cosx\cos x. We will take out cosx\cos x as a common factor. SO, we get the following equation,
cosx(2sinx1)=0\cos x\left( 2\sin x-1 \right)=0
Now, we have obtained two factors of the given expression such that their product is 0. We know that if the product of two numbers is 0, then either one of the two numbers has to be 0. Therefore, we have two possibilities, that is, either one of the factors in the above equation can be 0. So, we have either cosx=0\cos x=0 or 2sinx1=02\sin x-1=0.
If cosx=0\cos x=0, then we know that x=π2x=\dfrac{\pi }{2}. The cosine function is a periodic function with a period of 2π2\pi . Therefore, we have x=(2n+1)π2x=\left( 2n+1 \right)\dfrac{\pi }{2} where nn is a natural number.
If 2sinx1=02\sin x-1=0, we have sinx=12\sin x=\dfrac{1}{2}. We know that if sinx=12\sin x=\dfrac{1}{2}, then x=π6x=\dfrac{\pi }{6}. The sine function is a periodic function and its period is 2π2\pi . Therefore, we have x=π6+2πnx=\dfrac{\pi }{6}+2\pi n where nn is a natural number.
Therefore, the solution of the given equation is x=(2n+1)π2 or x=π6+2πnx=\left( 2n+1 \right)\dfrac{\pi }{2}\text{ or }x=\dfrac{\pi }{6}+2\pi n where nn is a natural number.

Note:
We should be familiar with the values of the trigonometric functions for standard angles. These values are useful in such types of questions. The double angle formulae and the half angle formulae are also essential in simplification of an equation. An important aspect of the trigonometric functions is their periodicity. A periodic function is a function that repeats its values after a fixed period.