Question

How do you solve ${\log _7}x + {\log _7}(x + 5) = {\log _7}(14)$?

Answer 1

In order to determine the value of the above question, rewrite the expression using the property of logarithm ${\log _b}(m) + {\log _b}(n) = {\log _b}(mn)$and take antilogarithm on both side to remove logarithm from the expression then use the splitting up the middle method to find the solution of the quadratic equation formed.

Formula:
${\log _b}(m) + {\log _b}(n) = {\log _b}(mn)$

Complete step by step solution:
We are Given an expression ${\log _7}x + {\log _7}(x + 5) = {\log _7}(14)$

Now, rewriting the expression using the property of logarithm ${\log _b}(m) + {\log _b}(n) = {\log _b}(mn)$
${\log _7}\left( {x(x + 5)} \right) = {\log _7}14$

Taking antilogarithm on both sides ,this will remove the logarithm from both the sides, our
expression now becomes

$$\Rightarrow x(x + 5) = 14 \\\ \Rightarrow {x^2} + 5x = 14 \\\ \Rightarrow {x^2} + 5x - 14 = 0 \\\$$

Expression has become a quadratic equation, and to solve this we’ll use splitting up the middle term method.

Follow below steps to split the middle term

Step 1: Calculate the product of coefficient of ${x^2}$and the constant term which comes to be $= - 14 \times 1 = - 14$

Step 2: Find the 2 factors of the number -14 such that the weather addition or subtraction of those numbers is equal to the middle term or coefficient of x and the product of those factors results in the value of constant .

So if we factorize 14, the answer comes to be 7and 2 as $7 - 2 = 5$ that is the middle term . and $7 \times 2 = 14$ which is perfectly equal to the constant value.

Now writing the middle term sum of the factors obtained, so equation becomes

$$\Rightarrow {x^2} + 7x - 2x - 14 = 0 \\\ \Rightarrow x(x + 7) - 2(x + 7) = 0 \\\ \Rightarrow (x + 7)(x - 2) = 0 \\\$$

$x + 7 = 0 \\\ \Rightarrow x = - 7 \\\ x - 2 = 0 \\\ \Rightarrow x = 2 \\\$
Value of x can be $- 7,2$

Since $\ln x$is not defined for the negative values of x so $x = 2$

Therefore, the solution to expression${\log _7}x + {\log _7}(x + 5) = {\log _7}(14)$is $x = 2$.

Note:
1.Value of constant ‘e’ is equal to $2.71828$.

2.A logarithm is basically the reverse of a power or we can say when we calculate a logarithm of any number, we actually undo an exponentiation.

3.Any multiplication inside the logarithm can be transformed into addition of two separate logarithm values.

${\log _b}(mn) = {\log _b}(m) + {\log _b}(n)$

4. Any division inside the logarithm can be transformed into subtraction of two separate logarithm values.
${\log _b}\left( {\dfrac{m}{n}} \right) = {\log _b}(m) - {\log _b}(n)$

5. Any exponent value on anything inside the logarithm can be transformed and moved out of the logarithm as a multiplier and vice versa.
$n\log m = \log {m^n}$

6.Quadratic Equation: A quadratic equation is a equation which can be represented in the form of $a{x^2} + bx + c$where $x$is the unknown variable and a,b,c are the numbers known where $a \ne 0$.If $a = 0$then the equation will become linear equation and will no more quadratic .