Question
Question: How do you solve\[{{\log }_{7}}3+{{\log }_{7}}x={{\log }_{7}}32\]?...
How do you solvelog73+log7x=log732?
Solution
In the given question, we have been asked to find the value of ‘x’ and it is given that log73+log7x=log732. In order to find the value of ‘x’, first we will apply the law of logarithm which states that logax=logbalogbx . Then we need to apply the product property of logarithm which states thatloga+logb=log(a×b) and simplify the equation further. After applying log formulae to the equation, we need to solve the equation in the way we solve general linear equations.
Complete step by step solution:
We have given,
log73+log7x=log732
Using the definition of logarithm, i.e.
logax=logbalogbx
Applying the definition of log, we get
⇒log(7)log(3)+log(7)log(x)=log(7)log(32)
Multiply both the sides of the equation by log (7), we get
⇒log3+logx=log32
Using the property of logarithm which states that if logs to the same base are added, then the numbers were multiplied, i.e. log (a) + log (b) = log (a.b)
⇒log(3x)=log(32)
Using the definition of log, if log (a) = log (b) then a = b.
Therefore,
⇒3x=32
Now solving for the value of ‘x’, we get
⇒x=332
Therefore, the value of x=332 is the required solution.
Formula used:
The definition of logarithm states that logax=logbalogbx
The property of logarithm which states that if logs to the same base are added, then the
numbers were multiplied, i.e. log (a) + log (b) = log (a.b).
Note: In the given question, we need to find the value of ‘x’. To solve these types of questions, we used the basic formulas of logarithm. Students should always be required to keep in mind all the formulae for solving the question easily. After applying log formulae to the equation, we need to solve the equation in the way we solve general linear equations.