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Question

Question: How do you solve\[{{\log }_{7}}3+{{\log }_{7}}x={{\log }_{7}}32\]?...

How do you solvelog73+log7x=log732{{\log }_{7}}3+{{\log }_{7}}x={{\log }_{7}}32?

Explanation

Solution

In the given question, we have been asked to find the value of ‘x’ and it is given that log73+log7x=log732{{\log }_{7}}3+{{\log }_{7}}x={{\log }_{7}}32. In order to find the value of ‘x’, first we will apply the law of logarithm which states that logax=logbxlogba{{\log }_{a}}x=\dfrac{{{\log }_{b}}x}{{{\log }_{b}}a} . Then we need to apply the product property of logarithm which states thatloga+logb=log(a×b)\log a+\log b=\log \left( a\times b \right) and simplify the equation further. After applying log formulae to the equation, we need to solve the equation in the way we solve general linear equations.

Complete step by step solution:
We have given,
log73+log7x=log732{{\log }_{7}}3+{{\log }_{7}}x={{\log }_{7}}32
Using the definition of logarithm, i.e.
logax=logbxlogba{{\log }_{a}}x=\dfrac{{{\log }_{b}}x}{{{\log }_{b}}a}
Applying the definition of log, we get
log(3)log(7)+log(x)log(7)=log(32)log(7)\Rightarrow \dfrac{\log \left( 3 \right)}{\log \left( 7 \right)}+\dfrac{\log \left( x \right)}{\log \left( 7 \right)}=\dfrac{\log \left( 32 \right)}{\log \left( 7 \right)}
Multiply both the sides of the equation by log (7), we get
log3+logx=log32\Rightarrow \log 3+\log x=\log 32
Using the property of logarithm which states that if logs to the same base are added, then the numbers were multiplied, i.e. log (a) + log (b) = log (a.b)
log(3x)=log(32)\Rightarrow \log \left( 3x \right)=\log \left( 32 \right)
Using the definition of log, if log (a) = log (b) then a = b.
Therefore,
3x=32\Rightarrow 3x=32
Now solving for the value of ‘x’, we get
x=323\Rightarrow x=\dfrac{32}{3}
Therefore, the value of x=323x=\dfrac{32}{3} is the required solution.
Formula used:
The definition of logarithm states that logax=logbxlogba{{\log }_{a}}x=\dfrac{{{\log }_{b}}x}{{{\log }_{b}}a}
The property of logarithm which states that if logs to the same base are added, then the
numbers were multiplied, i.e. log (a) + log (b) = log (a.b).

Note: In the given question, we need to find the value of ‘x’. To solve these types of questions, we used the basic formulas of logarithm. Students should always be required to keep in mind all the formulae for solving the question easily. After applying log formulae to the equation, we need to solve the equation in the way we solve general linear equations.