Question
Question: How do you solve \[\ln (x - 6) - \ln (5) = \ln (7) + \ln (x - 2)\] ?...
How do you solve ln(x−6)−ln(5)=ln(7)+ln(x−2) ?
Solution
Hint : In order to simplify the natural log equation with the formula is ln(x⋅z)=lnx+lnz and lnzx=lnx−lnz .The natural logarithm of a number is its logarithm to the base of the mathematical constant. The natural logarithm of x is generally written as lnx,logex or sometimes, if the base e is implicit, simply logx . We get the required solution by comparing the formula.
Formula:
ln(x⋅z)=lnx+lnz
lnzx=lnx−lnz .
Complete step-by-step answer :
In this problem,
The natural logarithm of the equation is ln(x−6)−ln(5)=ln(7)+ln(x−2) . First, we compare the equation with the formula is ln(x⋅z)=lnx+lnz and lnzx=lnx−lnz .
LHS = RHS
ln(x−6)−ln(5)=ln(7)+ln(x−2)
Comparing LHS equation, ln(x−6)−ln(5) with the formula lnzx=lnx−lnz , Subtraction of the log is the result of the source values being divided, where x=(x−6),z=5
LHS: ln(x−6)−ln(5)=ln(5x−6)
and Comparing RHS equation, ln(7)+ln(x−2) with the formula ln(x⋅z)=lnx+lnz ,Addition of logs is the consequence of the source values being multiplied. So
RHS: ln(7)+ln(x−2)=ln(7(x−2)) .
Combining all this equation together, we can get
ln(5x−6)=ln(7(x−2)
By remove the inverse of log on both side, we get
(5x−6)=(7(x−2)
Expanding the bracket on RHS and multiply by 5 on both sides, we have