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Question

Question: How do you solve \({k^2} = 76\)?...

How do you solve k2=76{k^2} = 76?

Explanation

Solution

In this question we have to solve the quadratic equation k2=76{k^2} = 76.Given equation is quadratic equation because it is of the form ax2+bx+c=0a{x^2} + bx + c = 0.Given a quadratic equation doesn’t have a term of the form bxbx. To solve this we need to know the quadratic formula and discriminant of a quadratic equation. Discriminant of a quadratic equation gives details about the nature of the roots of a quadratic equation.

Complete step by step answer:
Let us try to solve this question in which we are asked to solve for k2+0k76=0{k^2} + 0k - 76 = 0 equation k2=76{k^2} = 76. This equation can be written as k2+0k76=0{k^2} + 0k - 76 = 0. To solve this quadratic equation we will use quadratic formula and it is given by b±b24ac2a\dfrac{{ - b \pm \sqrt {{b^2} - 4ac} }}{{2a}} for any general quadratic equation ax2+bx+c=0a{x^2} + bx + c = 0 where b24ac{b^2} - 4ac is called the discriminant of quadratic equation, it tells the nature of roots of quadratic equation. Here are conditions:
-Two distinct real roots, if b24ac>0{b^2} - 4ac > 0
-Two equal real roots, if b24ac=0{b^2} - 4ac = 0
-No real roots, if b24ac<0{b^2} - 4ac < 0
In the given quadratic equation k2=76{k^2} = 76 we have,
a = 1 \\\ \Rightarrow b = 0 \\\ \Rightarrow c = - 76 \\\
Discriminant of the quadratic equation is
{b^2} - 4ac = {(0)^2} - 4 \cdot 1 \cdot ( - 76) \\\ \Rightarrow{b^2} - 4ac = 304 > 0 \\\
Hence the given quadratic equation has two distinct real roots, because discriminant is greater than 00.Now putting values of a,ba,band ccin quadratic formula we get,

k=b±b24ac2a k=(0)±(0)241(76)2 k=0±3042 k=±3042 k = \dfrac{{ - b \pm \sqrt {{b^2} - 4ac} }}{{2a}} \\\ \Rightarrow k= \dfrac{{ - (0) \pm \sqrt {{{(0)}^2} - 4 \cdot 1 \cdot ( - 76)} }}{2} \\\ \Rightarrow k= \dfrac{{0 \pm \sqrt {304} }}{2} \\\ \Rightarrow k = \dfrac{{ \pm \sqrt {304} }}{2} \\\

\Rightarrow k = \dfrac{{ \pm \sqrt {304} }}{2} \\\ \Rightarrow k= \dfrac{{ \pm \sqrt {16 \times 19} }}{2} \\\ \therefore k = \dfrac{{ \pm 4\sqrt {19} }}{2} \\\
Because we know that 16=±4\sqrt {16} = \pm 4. As we know 44 multiple of 22.

Hence the value of k=±219k = \pm 2\sqrt {19} .

Note: To solve questions in which you are asked to find the roots of quadratic equations by quadratic formula you must need to know the formula. We can also solve this by using other methods of finding roots of a quadratic equation such as completing square method and factor method.