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Question

Question: How do you solve for v in \[S=4{{v}^{2}}\]?...

How do you solve for v in S=4v2S=4{{v}^{2}}?

Explanation

Solution

This is a linear equation in one variable as there is only one variable in an equation as we treat S as a constant here. In the given question, the variable is the letter ‘v’, to solve this question we need to get ‘v’ on one side of the “equals” sign, and all the other numbers on the other side. To solve this equation for a given variable ‘v’, we have to undo the mathematical operations such as addition, subtraction, multiplication and division that have been done to the variables. For example- in the given equation we have 4v24{{v}^{2}} on the right-hand side, we can easily see that a number is multiplied by 4, so we undo this step by divide the number by 4 from the whole equation and this manner we get the solution of the question.

Complete step by step solution:
We have the given equation;
S=4v2S=4{{v}^{2}}
Dividing both the sides of equation by 4, we get
S4=4v24\Rightarrow \dfrac{S}{4}=\dfrac{4{{v}^{2}}}{4}
Simplifying the above, we get
S4=v2\Rightarrow \dfrac{S}{4}={{v}^{2}}
Transposing the power 2 to the other side of the equation, we get
S4=v\Rightarrow \sqrt{\dfrac{S}{4}}=v
As we know that 4=±2\sqrt{4}=\pm 2,
±S2=v\Rightarrow \pm \dfrac{\sqrt{S}}{2}=v
v=S2,S2\Rightarrow v=\dfrac{\sqrt{S}}{2},-\dfrac{\sqrt{S}}{2}
Therefore, the possible values of ‘v’ are S2\dfrac{\sqrt{S}}{2} and S2-\dfrac{\sqrt{S}}{2}.

Additional information: In the given question, no mathematical formula is being used; only the mathematical operations such as addition, subtraction, multiplication and division is used.
Use addition or subtraction properties of equality to gather variable terms on one side of the equation and constant on the other side of the equation.
Use the multiplication or division properties of equality to form the coefficient of the variable term equivalent to 1.

Note: The important thing to recollect about any equation is that the ‘equals’ sign represents a balance. What the sign says is that what’s on the left-hand side is strictly an equal to what’s on the right-hand side. It is the type of question where only mathematical operations such as addition, subtraction, multiplication and division is used.