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Question

Question: How do you solve \(\dfrac{n}{3} - 5 = 12\)?...

How do you solve n35=12\dfrac{n}{3} - 5 = 12?

Explanation

Solution

In order to determine the value of variablenn in the above equation use the rules of transposing terms to transpose terms having nnon the Left-hand side and constant value terms on the Right-Hand side of the equation. Solving like terms and multiplying both sides of the equation with the denominator of variablennwill lead to your required result.

Complete step by step solution:
We are given a linear equation in one variable n35=12\dfrac{n}{3} - 5 = 12.and we have to solve this equation for variable (xx).

n35=12 \Rightarrow \dfrac{n}{3} - 5 = 12

Now combining like terms on both of the sides. Terms having nnwill on the Left-Hand side of the equation and constant terms on the right-hand side .

Let’s recall one basic property of transposing terms that on transposing any term from one side to another the sign of that term gets reversed .In our case,5 - 5in the left hand side will become 55on the right hand side .

After transposing terms our equation becomes
n3=12+5\Rightarrow \dfrac{n}{3} = 12 + 5

Now, solving the Right-hand side, the value of nnis
n3=17\dfrac{n}{3} = 17

n = 51

Therefore, the solution to the equation n35=12\dfrac{n}{3} - 5 = 12is equal to n=51n = 51.

Note: Linear Equation: A linear equation is an equation which can be represented in the form of ax+cax + cwhere xxis the unknown variable and a,c are the numbers known where a0a \ne 0.

If a=0a = 0then the equation will become a constant value and will no longer be a linear equation .

The degree of the variable in the linear equation is of the order 1.