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Question: How do you solve \[\cos \left( \pi x \right)=0.5\] between the interval \[0\le x<2\]?...

How do you solve cos(πx)=0.5\cos \left( \pi x \right)=0.5 between the interval 0x<20\le x<2?

Explanation

Solution

This question is from the topic of trigonometry. In this question, we have to find the value of x. In solving this question, we will first know that at what range of x, the value of cosx will be positive. After that, we will know at what values of x, the value of cos(πx)=0.5\cos \left( \pi x \right)=0.5.

Complete step by step solution:
Let us solve this question.
In this question, we have asked to find the values of x from the given equation. The given equation is cos(πx)=0.5\cos \left( \pi x \right)=0.5. As the range of x is given as 0x<20\le x<2, so we will have to find the value of x in this range.
Let us first understand that at what values of x, the value of cos(πx)\cos \left( \pi x \right) will be positive.
Let us understand this from the following figure:

From the above figure, we can see that cos(πx)\cos \left( \pi x \right) is positive in
0πx<π20\le \pi x<\dfrac{\pi }{2} and 3π2<πx2π\dfrac{3\pi }{2}<\pi x\le 2\pi .
We can write the above range as
0x<120\le x<\dfrac{1}{2} and 32\dfrac{3}{2} < x2x \le 2
We will only take the range of x as 0x<20\le x<2 because it is given in the question.
Now, let us know that where the value of cos(πx)\cos \left( \pi x \right) is 0.5
cos(πx)=0.5\cos \left( \pi x \right)=0.5
We can write the above as
cos1(cos(πx))=cos1(0.5)co{{s}^{-1}}\left( \cos \left( \pi x \right) \right)=co{{s}^{-1}}\left( 0.5 \right)
The above can also be written as
πx=cos1(0.5)\Rightarrow \pi x=co{{s}^{-1}}\left( 0.5 \right)
We know that the value of cos1(0.5)co{{s}^{-1}}\left( 0.5 \right) is π3\dfrac{\pi }{3} and 5π3\dfrac{5\pi }{3} in the range of [0,2π]\left[ 0,2\pi \right]. We can see from the following figure:

From the above figure, we can say that the value of 0.5 is at the points π3\dfrac{\pi }{3} and 5π3\dfrac{5\pi }{3}.
So, we can say that
πx=π3\pi x=\dfrac{\pi }{3} and πx=5π3\pi x=\dfrac{5\pi }{3}
Or, we can say that
x=13x=\dfrac{1}{3} and x=53x=\dfrac{5}{3}
So, we get that the values of x for the interval 0x<20\le x<2 are 13\dfrac{1}{3} and 53\dfrac{5}{3}.

Note: We should have a better knowledge in the topic of trigonometry to solve this type of question easily. We should know the value of cos1(0.5)co{{s}^{-1}}\left( 0.5 \right) in radian between the range [0,2π]\left[ 0,2\pi \right]. The values of cos1(0.5)co{{s}^{-1}}\left( 0.5 \right) between that range are π3\dfrac{\pi }{3} and 5π3\dfrac{5\pi }{3}. We should know the graph of function cos, as they are very helpful in this type of question.