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Question

Question: How do you solve \[3\left( {2x - 1} \right) - 2\left( {3x + 4} \right) = 11x?\]...

How do you solve 3(2x1)2(3x+4)=11x?3\left( {2x - 1} \right) - 2\left( {3x + 4} \right) = 11x?

Explanation

Solution

This question describes the operation of addition/ subtraction/ multiplication/ division. To solve this type of question we need to move all the xx terms into one side and all the constant terms into another side to make the easy calculation. In this type of question first, we need to solve the operations inside the parenthesis. We would try to eliminate the parenthesis and make it a simple equation.

Complete step by step solution:
The given equation is shown below,
3(2x1)2(3x+4)=11x(1)3\left( {2x - 1} \right) - 2\left( {3x + 4} \right) = 11x \to \left( 1 \right)
At first, we would try to simplify the term3(2x1)3\left( {2x - 1} \right), it can be written as follows,
3(2x1)=6x3(2)3\left( {2x - 1} \right) = 6x - 3 \to \left( 2 \right)
Next, we would try to simplify the term2(3x+4) - 2\left( {3x + 4} \right), it can be written as follows,
2(3x+4)=6x8(3)- 2\left( {3x + 4} \right) = - 6x - 8 \to \left( 3 \right)
Let’s substitute the equations (2)\left( 2 \right)and(3)\left( 3 \right)in the equation(1)\left( 1 \right), we get

(1)3(2x1)2(3x+4)=11x 6x36x8=11x \left( 1 \right) \to 3\left( {2x - 1} \right) - 2\left( {3x + 4} \right) = 11x \\\ 6x - 3 - 6x - 8 = 11x \\\

To make an easy calculation, we would separate the xx terms into one side. So, we get
6x36x811x=06x - 3 - 6x - 8 - 11x = 0
Let’s separate the constant terms into another side, we get
6x6x11x=8+36x - 6x - 11x = 8 + 3
In the above equation+6x + 6xand6x - 6x can be canceled by each other. So we get
11x=11- 11x = 11
So, we need to find the value ofxx, for that let’s move 11 - 11to the right side of the equation.
So, we get

x=1111 x=1 x = \dfrac{{11}}{{ - 11}} \\\ x = - 1 \\\

So, the final answer is,
x=1x = - 1

Note: This type of question involves the operation of addition/ subtraction/ multiplication/ division. We would find the value of xx, for that, we should arrange the xx terms into one side and constant terms into another side. If the negative sign is present in the denominator we can move it to the numerator.
Also, note the following things when multiplying different sign terms,

  1. When a negative number is multiplied with a negative number, the answer becomes
    positive.
  2. When a positive number is multiplied with a negative number, the answer becomes
    negative.
  3. When a positive number is multiplied with the positive number the answer becomes
    positive.